Probability Question - Urn problem

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Homework Help Overview

The problem involves an urn containing 4 white and 4 black balls, from which 4 balls are randomly selected. The process continues until exactly 2 of the selected balls are white and 2 are black. The question seeks to determine the probability of making exactly n selections before achieving this outcome.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of calculating the probability of drawing exactly 2 white balls and question the validity of the approach used, particularly regarding the assumption of simultaneous selection.

Discussion Status

Some participants have offered insights into the assumptions made about the selection process, noting that the probability of drawing a white ball changes based on previous selections. There is an ongoing exploration of the sample space and the conditions under which the selections are made.

Contextual Notes

Participants are grappling with the implications of drawing balls sequentially versus simultaneously, which affects their understanding of the probabilities involved.

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Homework Statement



An urn contains 4 white and 4 black balls. We randomly choose 4 balls. IF 2 of them are white and 2 are black, we stop. If not, we replace the balls in the urn and again randomly select 4 balls. this continues until exactly 2 of the 4 chosen are white. What is the probability that we shall make exactly n selections.

Homework Equations





The Attempt at a Solution



I don't see why I can't find the probability of drawing exactly 2 white balls using this method.

(4C2)(4/8)^2(1-4/8)^2
where 4C2 is 4 choose 2

apparently this is wrong but I don't see why. Thanks for any help that you can provide.
 
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GreenPrint said:

Homework Statement



An urn contains 4 white and 4 black balls. We randomly choose 4 balls. IF 2 of them are white and 2 are black, we stop. If not, we replace the balls in the urn and again randomly select 4 balls. this continues until exactly 2 of the 4 chosen are white. What is the probability that we shall make exactly n selections.

Homework Equations





The Attempt at a Solution



I don't see why I can't find the probability of drawing exactly 2 white balls using this method.

(4C2)(4/8)^2(1-4/8)^2
where 4C2 is 4 choose 2

apparently this is wrong but I don't see why. Thanks for any help that you can provide.

Well, why do you think it's right? The probability of choosing a white ball is only 1/2 the first time you choose a ball. It's not always 1/2, is it?
 
oh i guess i always assumed you pick the things simultaneously as that's what I've been doing throughout the course so i guess this assumption is wrong?
 
GreenPrint said:
oh i guess i always assumed you pick the things simultaneously as that's what I've been doing throughout the course so i guess this assumption is wrong?

If you pick a white ball first that means there are 3 whites left and 4 blacks. The odds of picking a second white or a black aren't 1/2 anymore. So yes, it's wrong.
 
I think it is always useful to describe the sample space: you can succeed the 1st, or the 2nd time, etc.

EDIT: I mean, you can select the two balls in the first trial, or, if you don't, then at the second trial, etc.
 
Last edited:

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