Probability of 25-30 Correct Answers on 200-Q Quiz

  • Thread starter Thread starter etotheix
  • Start date Start date
  • Tags Tags
    Probability
Click For Summary
SUMMARY

The discussion focuses on calculating the probability of achieving between 25 to 30 correct answers on a 200-question multiple-choice quiz using binomial distribution. The participants utilize the formula for binomial probability, specifically P(X=k) = (n choose k)p^k(1-p)^(n-k), where n is the total number of questions, k is the number of correct answers, and p is the probability of a correct answer. A suggestion to use the normal distribution as an approximation to the binomial distribution is emphasized as the correct approach, rather than dividing the problem into smaller segments.

PREREQUISITES
  • Understanding of binomial distribution and its formula
  • Familiarity with combinatorial mathematics (n choose k)
  • Basic knowledge of probability theory
  • Experience with normal distribution as an approximation
NEXT STEPS
  • Learn about the normal approximation to the binomial distribution
  • Study the Central Limit Theorem and its applications in probability
  • Explore combinatorial techniques for calculating probabilities
  • Practice solving problems involving binomial and normal distributions
USEFUL FOR

Students studying probability, educators teaching statistics, and anyone interested in understanding binomial distributions and their approximations.

etotheix
Messages
21
Reaction score
0

Homework Statement



A multiple-choice quiz has 200 questions each with 4 possible answers of which 1 is correct. What is the probability that guesswork yields from 25 to 30 correct answers for 80 of the 200 questions. [HINT: approximation may be helpful here]

Homework Equations



Binomial distribution
(n choose x)p^x*(1-p)^(n-x)

The Attempt at a Solution



Since 80! is too big of a number and I can't calculate for instance (80 chose 25) I decided to divide everything by 5, I am not sure if this is what the hint is indicating.

Now I have 16 questions and I have to find the probability of answering correctly from 5 to 6.

Event A: answer 5 questions correctly
Event B: answer 6 questions correctly

I am looking for P(A OR B) = P(A) + P(B) - P(A AND B)

P(A)=(16 choose 5)(0.25)^5*(0.75)^11=0.18
P(B)=(16 choose 6)(0.25)^6*(0.75)^10=0.11
P(A AND B)=0

P(A OR B)=0.18 + 0.11 = 0.29 or 29%

Is this the correct way? I am mostly confused because of the "from 25 to 30" and I am not sure if the division by 5 is correct.

Thank you in advance.
 
Physics news on Phys.org
I think when it says use an approximation it means use the normal distribution as an approximation to the binomial distribution, not divide everything by 5.
 
danago said:
I think when it says use an approximation it means use the normal distribution as an approximation to the binomial distribution, not divide everything by 5.

Thank you, I believe you are absolutely right. I am fairly new to probability as you can see.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 24 ·
Replies
24
Views
2K
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
12
Views
4K
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K