Probability Questions Before College: Tablets & Taste Test

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Homework Help Overview

The discussion revolves around probability questions related to a company's tablet disintegration test and a taste test involving two products. The original poster seeks assistance in understanding how to calculate probabilities in these contexts.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate the probability of at least 4 out of 6 tablets passing a disintegration test, expressing uncertainty about the use of the percentage provided. They also explore the implications of a taste test where 6 out of 8 participants identify a product with an additive, questioning how to justify this finding using probability.

Discussion Status

Participants are engaging in exploratory dialogue, with some offering guidance on how to approach the taste test question by considering random selection. There is an ongoing exchange about the calculations needed for both problems, with no explicit consensus reached yet.

Contextual Notes

The original poster mentions feeling blocked on the first question and is unsure about the calculations, indicating a potential gap in understanding the application of probability concepts. There is also a hint of confusion regarding the phrasing of the second question.

B2k
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jus before i go back to college trying to get a bit of revision done..
however i seem to have a block on this probability question...

a company makes tablets.. 94% would pass a disintegration test.. an inspector selects 6 at random at least 4 would have to pass, what is the proability of passing this test..?

and.. a study is conducted with 8 people tasting two products.. one with an additive.. 6 people select as product one having the additive.. can people tell a difference? use probability to justify your answer.. just wondering how best to prove that statement?
 
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What have you tried for each one?
 
well for the second part its obvious that people can tell a difference if 6 can identify it.. that's just a straightforward probability q that can be done with the formula p=a/s.. i can do the math for that.. just how to phrase it..

the first part, I am a bit stumped.. the answers i get seem far out.. I am not sure am i using the % part of it right..
 
Welcome to PF!

Hi B2k! Welcome to PF! :smile:
B2k said:
the first part, I am a bit stumped.. the answers i get seem far out.. I am not sure am i using the % part of it right..

So show us what you've done … :wink:
 
Here's how I would approach #2. Consider what happens if people CANNOT tell the difference between the two products and just choose randomly. What is the probability that 6/8 choose the correct product?
 
You replied
Ygggdrasil said:
Here's how I would approach #2. Consider what happens if people CANNOT tell the difference between the two products and just choose randomly. What is the probability that 6/8 choose the correct product?

Almost. If they cannot tell the difference, and simply make selections at random, you want the probability that at least six of the eight choose this way?

What type of calculation do you need to do to find that probability?
 

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