# Homework Help: Math *Questions* Involving Probablity

1. Apr 27, 2012

### darshanpatel

1. The problem statement, all variables and given/known data

1) How many times must you roll two six-sided dice for there to be at least a 50% chance that you roll two 6's at least once?

2) It is estimated that 5.9% of Americans have diabetes. Suppose a medical lab uses a test for diabetes that 98% accurate for people who have the disease and 95% accurate for the people who do not have it. Find the conditional probability that a randomly selected person actually has diabetes given that the lab test says they have it.

2. Relevant equations

-None-

3. The attempt at a solution

Question One:

Work: chance of rolling a six(dice one) x chance of rolling a six(dice two) x one half

1/6 x 1/6 x 1/2 = 1/72

72 rolls?

Question Two:

Work:

P(accurate) x (accurate|don't have diabetes) - P(accurate) x (accurate|have diabetes)
(.95 x .941)-(.98 x .059)= .89395-.83163 = about 5.782% ?

2. Apr 27, 2012

### Staff: Mentor

q1: mathematicians look at this problem in reverse and instead ask whats the probability of not getting two sixes in a row and then multiply it over and over until they get to the 50% mark and the number of times they multiplied will be the number of rolls needed.

q2: is a a bayesian conditional probability question, you need the bayes eqn to compute it:

p(A given B) = p(B given A) * p(A) / p(B) or succinctly p(A|B)=p(B|A)p(A)/p(B)

where A= prob of having diabetes and B=prob of positive test

3. Apr 28, 2012

### Villyer

My approach to problem two was to set an arbitrary number of people in the population (say 1 million) and then figure out the number of people who A) have the disease and get a positive test result and then B) don't have the disease, but still get a positive result.
Then the answer is A/(A+B), which was ~55%

I only approached the problem this way because I'm not familiar with bayesian equation that jedishrufu mentioned.

4. Apr 28, 2012