Probability/Schrodinger's equation

  • Thread starter Thread starter NicolasM
  • Start date Start date
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 2K views
NicolasM
Messages
3
Reaction score
0
We have a hydrogen atom in its ground state. What is the probability of an electron being found within a sphere (with nucleus being the origin) of a radius of 2[itex]a_{o}\ =\ 0.5291772083(19)\ \times\ 10^{-10}α\ m[/itex]?

Would 0 4πr3ψ2dr/3 x100% be correct?
 
Physics news on Phys.org
NicolasM said:
We have a hydrogen atom in its ground state. What is the probability of an electron being found within a sphere (with nucleus being the origin) of a radius of 2[itex]a_{o}\ =\ 0.5291772083(19)\ \times\ 10^{-10}α\ m[/itex]?

Would 0 4πr3ψ2dr/3 x100% be correct?

No, it wouldn't even have correct dimensions. Why do you think that's right? Work it out from the three dimensional integral of |ψ|^2. Your differential factor is wrong.
 
Last edited: