Probability that Bill told the truth problem

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SUMMARY

The probability that Bill told the truth, given that Harry claims he did, can be calculated using Bayes' theorem. Bill tells the truth with a probability of 0.5, while Harry tells the truth with a probability of 2/3. The four possible outcomes are (H|B), (H'|B), (H|B'), and (H'|B'). To determine the probability P(B|H), one must apply the formula P(H|B) * P(B) / P(H), where P(H) is the total probability of Harry telling the truth.

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Bill tells the truth one-half of the time and Harry tells the truth two-thirds of the time. Bill says something, and Harry, who knows whether Bill told the truth, says, "Bill just told the truth". What is the probability that Bill told the truth?

Let:
B = Bill told the truth
B' = Bill lied
H = Harry told the truth
H' = Harry Lied

P(B) = .5
P(B') = .5
P(H) = 2/3
P(H') = 1/3


So there should be 4 possible outcomes.. (H|B), (H'|B), (H|B'), (H'|B').

I know that there is an equation for each of these, like P(H|B) = P(H|B)/P(B|H) or something like that I'm just not sure which equation to use. Please help! Thanks!
 
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http://en.wikipedia.org/wiki/Conditional_probability" may help.
 
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