- #1

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G1 make up 30% of drivers, G2 make up 50% of drivers, and G3 make up the remaining 20% of drivers.

P(at least one accident for G1)=0.1 = P(A1)

P(at least one accident for G2)=0.3 = P(A2)

P(at least one accident for G3)=0.5 = P(A3)

If we randomly select a driver out of the groups and the driver has no accident, what is probability that the driver is from G3?

I tried [tex]P(G3 | (A1^{c} \cap A2^{c} \cap A3^{c}))[/tex]. Is this is the right method of solving such a question? The probability I got from this happened to be zero which sort of confirms that it's incorrect. Any advice will be great.

Thanks a lot.