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Probability when rolling 6 true dice

  1. Oct 23, 2011 #1
    Hello,

    So the question is: You have 6 true dice and you want to find the probability of rolling exactly two aces (im assumming ace means 1).
    I tried using the binomial theroem:
    P = (6!/(2!4!)) (1/6)^2 (5/6)^4 = 0.2009
    But the answer is 0.040..So where did I go wrong?

    Thanks
    DoubleMint
     
  2. jcsd
  3. Oct 23, 2011 #2

    Ray Vickson

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    Science Advisor
    Homework Helper

    Your answer is correct; you did nothing wrong.

    RGV
     
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