Probabilty an event will occur

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SUMMARY

The discussion centers on calculating the probability of an event occurring based on its average frequency. If an event occurs once every 10 days, the daily probability is 1/10. The probability of the event occurring within a specified number of days can be calculated using the formula: 1 - (probability of non-occurrence)^number of days. For instance, the probability of the event occurring at least once in the next two days is 1 - (9/10)^2. This method simplifies calculations for longer timeframes, such as 14 days.

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cpscdave
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Can someone confirm if I'm going about this the right way

If I have an event that on average has occurred once every 10 days.
The probability of that event occurring on any given day is 1/10
so then the probability the event occur tommorow 1/10
the probability the event will occur within the next 2 days is:
(1-1/10)*1/10+1/10
Pobabilty the event didnt occur on the first day but on the second plus the probability the event occurred on the first day.
And so on for 3 days, 4 days etc etc etc

Thanks!
-Dave
 
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Assuming the events occur independently of each other (for example, if it happens it is just as likely to happen again tomorrow as usual), then I think your analysis is sound.

Notice you could solve that 2 day problem slightly easier (which makes solving. e.g. the 8 day problem much easier). The probability that it occurs in the next two days is one minus the probability it does not occur. The probability it does not occur in either of the next two days is simply (9/10)2, so the probability it occurs at least once in the next two days is 1-(9/10)2. Not too helpful for in the next two days, but if someone wanted you to find the probability the event occurs in the next 14 days, for example, then this would make your expression a lot simpler.
 
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