Problem, i went wrong somewhere

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Homework Help Overview

The problem involves five newsboys selling papers in a specific manner, where the sales of Tom Smith, Billy Jones, Ned Smith, and Charley Jones are defined in relation to the total number of papers. The Smith boys collectively sold one hundred papers more than the Jones boys, and the task is to determine how many more papers the Jones boys sold compared to the Smith boys.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss their interpretations of the problem and the relationships between the quantities sold by each newsboy. There are attempts to set up equations based on the problem statement, with some questioning their algebraic manipulations and assumptions about the quantities involved.

Discussion Status

Some participants are actively exploring their calculations and questioning where they may have made errors. There is a recognition of the complexity of the relationships between the sales figures, and at least one participant suggests a potential revision to their algebraic representation of the problem.

Contextual Notes

Participants note that the total number of papers must be an integer, raising concerns about non-integer results in their calculations. There is also a mention of needing to relate the algebraic expressions to the actual number of papers sold.

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im stuck on this problem, which is annoying because it looks straightforward, i think i just made a clanger somewhere and can't find where lol, hope you can help... thnx

Homework Statement



Five clever newsboys formed a partnership and disposed of their papers in the following manner. Tom Smith sold one paper more than one quarter of the whole lot, Billy Jones disposed of one paper more than a quarter of the remainder, Ned Smith sold one paper more than a quarter of what was left, and Charley Jones disposed of one paper more than a quarter of the remainder. At this stage, the Smith boys had together sold just one hundred papers more than the Jones boys had sold. Little Jimmy Jones, the youngest kid in the bunch, now sold all the papers that were left.

The three Jones boys sold more papers than the two Smith boys, but how many more?

2. Notation

Tom Smith = T
Billy Jones = B
Ned Smith = N
Charley Jones = C
Jimmy Jones = J

Total number of papers = t

The Attempt at a Solution



What I gathered from the problem statement.

T = 1/4t + 1
B = 3/16t
N = 9/64t
C = 27/256t
T + N - 100 = B + C
J = 81/256t - 1

From that I substituted the letters into T + N - 100 = B + C

T + N - 100 = B + C
1/4t + 1 + 9/64t - 100 = 3/16t + 27/256t
1/4t + 9/64t - 99 = 3/16t + 27/256t
25/64t - 99 = 75/256t
25/64t = 75/256t + 99
25/256t = 99
t = 1013 19/25 ??

there can't be a non integer as the no of papers?

im confused, i think i went wrong at some poitn but can't find where, can anyone help? thnx
 
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Trail_Builder said:
im stuck on this problem, which is annoying because it looks straightforward, i think i just made a clanger somewhere and can't find where lol, hope you can help... thnx

Homework Statement



Five clever newsboys formed a partnership and disposed of their papers in the following manner. Tom Smith sold one paper more than one quarter of the whole lot, Billy Jones disposed of one paper more than a quarter of the remainder, Ned Smith sold one paper more than a quarter of what was left, and Charley Jones disposed of one paper more than a quarter of the remainder. At this stage, the Smith boys had together sold just one hundred papers more than the Jones boys had sold. Little Jimmy Jones, the youngest kid in the bunch, now sold all the papers that were left.

The three Jones boys sold more papers than the two Smith boys, but how many more?

2. Notation

Tom Smith = T
Billy Jones = B
Ned Smith = N
Charley Jones = C
Jimmy Jones = J

Total number of papers = t

The Attempt at a Solution



What I gathered from the problem statement.

T = 1/4t + 1
B = 3/16t
After removing Tom Smiths papers, there were t- (1/4)t- 1= (3/4)t-1 papers left. We are told that "Billy Jones disposed of one paper more than a quarter of the remainder": B= (1/4)((3/4)t-1)+ 1= (3/16)t- 1/4+ 1=
(3/16)t+ 3/4. You forgot to take 1/4 of the original "one paper less"

N = 9/64t
"Ned Smith sold one paper more than a quarter of what was left"
"What was left" is now (3/4)t- 1- ((3/16)t+ 3/4)= (9/16)t- 7/4. 1/4 of that is (1/4)((9/16)t- 7/4)= (9/64)t- 7/16. "One paper more" is (9/64)t- 7/16+1= (9/64)t+ 9/16.

C = 27/256t
T + N - 100 = B + C
J = 81/256t - 1

From that I substituted the letters into T + N - 100 = B + C

T + N - 100 = B + C
1/4t + 1 + 9/64t - 100 = 3/16t + 27/256t
1/4t + 9/64t - 99 = 3/16t + 27/256t
25/64t - 99 = 75/256t
25/64t = 75/256t + 99
25/256t = 99
t = 1013 19/25 ??

there can't be a non integer as the no of papers?

im confused, i think i went wrong at some poitn but can't find where, can anyone help? thnx
 
Last edited by a moderator:
Trail_Builder said:
At this stage, the Smith boys had together sold just one hundred papers more than the Jones boys had sold.

...

T + N - 100 = B + C

wait, i think i might know where i went wrong, when turning the quoted sentence into algabra , is it the case that i need to relate it to the number of papers sold so far?

so should that line look like this?

T(175/256t + 1) + N(175/256t + 1) - 100 = B(175/256t + 1) + C(175/256t + 1)


?

thnx
 
o rite yeh just saw that reply, thnx buddy
 

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