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**1. Homework Statement**

Five clever newsboys formed a partnership and disposed of their papers in the following manner. Tom Smith sold one paper more than one quarter of the whole lot, Billy Jones disposed of one paper more than a quarter of the remainder, Ned Smith sold one paper more than a quarter of what was left, and Charley Jones disposed of one paper more than a quarter of the remainder. At this stage, the Smith boys had together sold just one hundred papers more than the Jones boys had sold. Little Jimmy Jones, the youngest kid in the bunch, now sold all the papers that were left.

The three Jones boys sold more papers than the two Smith boys, but how many more?

**2. Notation**

Tom Smith = T

Billy Jones = B

Ned Smith = N

Charley Jones = C

Jimmy Jones = J

Total number of papers = t

**3. The Attempt at a Solution**

What I gathered from the problem statement.

T = 1/4t + 1

B = 3/16t

N = 9/64t

C = 27/256t

T + N - 100 = B + C

J = 81/256t - 1

From that I substituted the letters into T + N - 100 = B + C

T + N - 100 = B + C

1/4t + 1 + 9/64t - 100 = 3/16t + 27/256t

1/4t + 9/64t - 99 = 3/16t + 27/256t

25/64t - 99 = 75/256t

25/64t = 75/256t + 99

25/256t = 99

t = 1013 19/25 ??

there cant be a non integer as the no of papers????

im confused, i think i went wrong at some poitn but cant find where, can anyone help? thnx