What is the velocity of an electron at t = 1.22 s, given its position function?

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The position function of the electron is given as 3.56t - 8.10t² + 2.53. At t = 1.22 s, the x-component of velocity is determined to be 3.56 m/s, while the y-component was initially miscalculated but later corrected. The magnitude of the velocity was also recalculated, leading to confusion regarding its value. The angle relative to the positive x-axis was found to be negative due to the negative y-component. Ultimately, the user resolved the issues by taking the derivative of the position function to find the correct velocity components.
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This should be a really easy problem but for some reason I keep getting the wrong answers.

The position of an electron is given by = 3.56t - 8.10t2 + 2.53, with t in seconds and in meters. At t = 1.22 s, what are (a) the x-component, (b) the y-component, (c) the magnitude, and (d) the angle relative to the positive direction of the x axis, of the electron's velocity ?

a) I got the answer to be 3.56 m/s
b) I thought was -8.10 m/s^2 but for some reason it is wrong or atleast this online homework is telling me it is
c) I used the magnitude function to find it for the time being 1.22s
sqrt(4.34^2 + (12.056)^2 + (2.53)^2) and I get 13.06m but it also tells me I am wrong with that.
d) then I can't find this out because I have the magnitude wrong. But if I did have it right I would have it to be arcCos(3.56/magnitude) right?

any help would be great thanks :)
 
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figured out part b and c as I got to the end of the problem I saw they wanted it in velocity so I had to take the derivative of r and then solve for x and y values.

I am still having trouble with d though...
 
I figured it out it ended up being a negative value because my y-component is negative which would make the magnitude of the vectors in the negative direction, and that gives me -79.79.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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