Problem of the Week #116 - August 18th, 2014

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SUMMARY

The discussion centers on the problem of defining a pairing using the function $P:V\times V\rightarrow\mathbb{C}$, where $V$ is the Schwarz space of smooth functions. The integral $P(f,g)=\int_{-\infty}^{\infty}f(x)g(x)\,dx$ is confirmed to define a pairing, as it satisfies linearity in both arguments. However, the non-degeneracy of $P$ remains under investigation, with partial solutions provided by user Ackbach. The community is encouraged to contribute further insights on the non-degenerate aspect of the pairing.

PREREQUISITES
  • Understanding of Schwartz space and its properties
  • Familiarity with integration of complex functions
  • Knowledge of linear algebra concepts, particularly pairings
  • Experience with calculus, specifically differentiation and integration techniques
NEXT STEPS
  • Research the properties of Schwartz space and its applications in functional analysis
  • Explore the concept of non-degenerate pairings in vector spaces
  • Study the implications of linearity in integrals involving smooth functions
  • Investigate further examples of pairings in mathematical literature
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Mathematicians, students of functional analysis, and anyone interested in the properties of smooth functions and their integrals will benefit from this discussion.

Chris L T521
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Here's this week's problem!

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Problem
: Let $V$ be the vector space of smooth (i.e. infinitely-differentiable) functions $f:\mathbb{R}\rightarrow\mathbb{C}$ such that for all $m,n\in\mathbb{N}$, there exists $C_{m,n}>0$ for which$$\forall\,x\in\mathbb{R},\,(1+x^2)^m\cdot|f^{(n)}(x)|\leq C_{m,n}.$$
This is called the Schwarz space - its elements are smooth functions all of whose derivatives decay rapidly. Define a function $P:V\times V\rightarrow\mathbb{C}$ by
$$P(f,g)=\int_{-\infty}^{\infty}f(x)g(x)\,dx.$$
Does $P$ define a pairing? Is $P$ nondegenerate?

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This week's delays are brought to you by yours truly starting work again now that Fall semester is underway.

This week's problem was partially correctly answered by Ackbach. As for the case of whether or not the pairing is non-degenerate, I too am still working on that part and I hope to have a solution posted sometime in the next couple days.

Without much further ado, you can find Ackbach's partial solution below.

[sp]$P$ definitely defines a pairing. Check:
$\begin{align*}
P(r f,g)&=\int_{-\infty}^{\infty}(rf(x))g(x) \, dx \\
&=\int_{-\infty}^{\infty}f(x)(rg(x)) \, dx \\
&=P(f,rg) \\
&=r \int_{-\infty}^{\infty}f(x) g(x) \, dx \\
&=r P(f,g).
\end{align*}$
Moreover,
$\begin{align*}
P(f+g,h)&=\int_{-\infty}^{\infty}(f(x)+g(x))h(x) \, dx \\
&=\int_{-\infty}^{\infty}f(x) h(x) \, dx+\int_{-\infty}^{\infty}g(x) h(x) \, dx \\
&=P(f,h)+P(g,h),
\end{align*}$
and similarly, $P(f,g+h)=P(f,g)+P(f,h)$. Thus, $P$ satisfies all the requirements for a pairing.[/sp]
 

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