Problem on Conservation of energy

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SUMMARY

The discussion centers on a physics problem involving two blocks, A (50 kg) and B (100 kg), connected by a string over a frictionless pulley. The objective is to determine their speeds after block A slides a distance of 0.25 m. The initial attempt incorrectly calculated the final speed as 2.42 m/s, while the correct answer is 1.51 m/s. Key errors included mixing initial and final velocities and neglecting the energy changes for both blocks.

PREREQUISITES
  • Understanding of kinetic energy (K = 0.5mv²)
  • Familiarity with potential energy (P = mgh)
  • Knowledge of energy conservation principles
  • Basic trigonometry for resolving forces on an incline
NEXT STEPS
  • Review the principles of energy conservation in mechanical systems
  • Study the effects of frictionless pulleys on connected masses
  • Learn how to apply trigonometric functions to inclined planes
  • Practice solving similar problems involving multiple objects and energy transformations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to clarify common misconceptions in energy problems.

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Homework Statement



Two blocks, A and B (mA=50 kg and mB=100 kg), are connected by a string as
shown. If the blocks begin at rest, what will their speeds be after A has slid
a distance d = 0.25 m? Assume the pulley and incline are frictionless.

Homework Equations



K= .5mv^2
P=mgh
ke(initial) + pe(initial) = kef = pef


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The Attempt at a Solution



.5mvi^2 + mghi = .5mvf^2 + mghf (at rest)
.5mvf^2 = -mghf
.5(50 kg) vf^2 = -100(-9.8)(.25sin37)
vf = 2.42 m/s which is wrong... where did i go wrong? the ans. is 1.51 m/s
 
Physics news on Phys.org
You have your vf and vi mixed up, but beyond that, do not forget that both blocks have a change in their potential and kinetic energies.
 

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