Problem solving calculating area

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    Area Problem solving
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The discussion centers on solving a mathematical problem involving the calculation of area using a given perimeter of 200 feet for a fenced square. The equations derived include $2W + L = 200$ and conditions that lead to $W \ge 30$ and $L \ge 100$. The final calculation for the area of the square formed by the fencing is $\left(\dfrac{200}{3}\right)^2 \text{ ft}^2$, which converts to approximately 493.8 square yards. The conversation also touches on the educational context, indicating that such problems are typically encountered in Grade 11 mathematics in Indonesia.

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I help students a bit with their math. As a teacher I am over 35 years removed from Math so I am rusty. I had the following questions given to me by some students and I couldn't even remember.View attachment 9317View attachment 9318View attachment 9316

The students are required to show their work how to solve this problem.
 

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$2W + L = 200$

$2W = 200 - L$

condition (1) ... $W \ge 30 \implies 2W \ge 60 \implies 200-L \ge 60 \implies L \le 140$

condition (2) ... $L \ge 2W \implies L \ge 200-L \implies L \ge 100$If a square is made, each side of the fence would have what dimension in feet given the 200 ft of available fencing?

Square that dimension. Recall $9 \text{ ft}^2 = 1 \text{ yd}^2$
 
In which grade level does one normally find this kind of equality question? I simply can't remember actually ever studying this kind of question type. Is there a name for this type of question i.e. equalities? I am still at a loss on how to calculate the 2nd question.
Thank you again.
 
Last edited:
einie101 said:
In which grade level does one normally find this kind of equality question? I simply can't remember actually ever studying this kind of question type. Is there a name for this type of question i.e. equalities? Thank you again.

In my country, it's for Grade 11. Dunno how that applies to Western countries, though.
 
Monoxdifly said:
In my country, it's for Grade 11. Dunno how that applies to Western countries, though.
I'm in Jakarta presently . .. is that using an International curriculum (i.e. Cambridge/Oxford etc.) or the National Indonesian Curriculum (I see you are in Indonesia).
 
einie101 said:
... I am still at a loss on how to calculate the 2nd question.

200 ft of fencing form three of the four equal sides of the square with the fourth side being the side of the building.

Each side of fence is $\dfrac{200}{3} \text{ ft}$

area of the square formed is $\left(\dfrac{200}{3}\right)^2 \text{ ft}^2$

remember you’ll need to convert square feet into square yards ... I supplied the conversion relationship in my initial post
 
The answer is supposed to be 493.8 . . . if I take (200/3)2 = 66.67 * 66.67 = 4444.4 then divide this number by 9 I get the answer . . . I was not remembering this step . . . boy my math muscles are weak. The difficulty to add insult to injury is that over here in Asia the imperial system is unfamiliar . . .
 
Last edited:
einie101 said:
I'm in Jakarta presently . .. is that using an International curriculum (i.e. Cambridge/Oxford etc.) or the National Indonesian Curriculum (I see you are in Indonesia).

I see. I was wondering because your profile says that your location is in Jakarta but it has a Canadian flag.
It's the National Indonesian Curriculum.
 

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