Problem Solving: Is My Solution Right?

[monty37]

do tell me if the way i did this problem is right!

q::An object is thrown vertically upward with a velocity of 30m/s.Four seconds later
a second object is projected vertically with a velocity of 40 m/s .determine i)time(after first object is thrown)when two objects will meet each other in air ii) height from Earth when two objects meet

my probable solution:consider first object time as t and second object time as t+4,
solve for t by equating their maximum height formula(s=ut+0.5gt^2) ?

 

[diazona]

But what makes you think the two objects will reach the same maximum height?

 

[monty37]

why do you think max.height is not the same,as you throw the first object at time t
and second ,time difference is t+4,or maybe iam wrong... please give me a solution then..