Luna=Luna
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"It is left as a problem for the reader to show that if [itex][S,T][/itex] commutes with S and T, then [itex][e^{tT}, S] = -t[S,T]e^{tT}[/itex]
I'm not sure if I'm missing something here, but i don't even see how it is possible to arrive at this answer.
I get:
[tex][e^{tT}, S] = e^{tT}S - Se^{tT}[/tex]
Then using the fact that [itex][S,T][/itex] commutes with S and T this gives:
[itex]SST-STS = STS-TSS[/itex]
and
[itex]TST-TTS = STT-TST[/itex]
and see no way to go further.
One major thing is I don't even see how the factor of -t just appears in the identity?
[itex][e^{tT}, S] = -t[S,T]e^{tT}[/itex]
I'm not sure if I'm missing something here, but i don't even see how it is possible to arrive at this answer.
I get:
[tex][e^{tT}, S] = e^{tT}S - Se^{tT}[/tex]
Then using the fact that [itex][S,T][/itex] commutes with S and T this gives:
[itex]SST-STS = STS-TSS[/itex]
and
[itex]TST-TTS = STT-TST[/itex]
and see no way to go further.
One major thing is I don't even see how the factor of -t just appears in the identity?
[itex][e^{tT}, S] = -t[S,T]e^{tT}[/itex]