Problem understanding operator algebra

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SUMMARY

The discussion centers on the operator algebra involving the commutation relation [S,T] and its implications for the expression [e^{tT}, S]. It is established that if [S,T] commutes with both S and T, then the identity [e^{tT}, S] = -t[S,T]e^{tT} holds true. The participants express confusion regarding the derivation of this result, particularly the emergence of the factor -t. The use of Taylor expansion for operator functions is suggested as a method to approach this problem.

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  • Familiarity with Taylor series expansions in the context of operators
  • Knowledge of exponential operators, specifically e^{tT}
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Luna=Luna
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"It is left as a problem for the reader to show that if [S,T] commutes with S and T, then [e^{tT}, S] = -t[S,T]e^{tT}

I'm not sure if I'm missing something here, but i don't even see how it is possible to arrive at this answer.

I get:
[e^{tT}, S] = e^{tT}S - Se^{tT}

Then using the fact that [S,T] commutes with S and T this gives:

SST-STS = STS-TSS
and
TST-TTS = STT-TST

and see no way to go further.
One major thing is I don't even see how the factor of -t just appears in the identity?
[e^{tT}, S] = -t[S,T]e^{tT}
 
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The typical way to do something like this would be to use a Taylor expansion of the function of the operator, in this case e^{tT}. What you were trying to show is an example of a more general result.
 

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