Problem with the definition of work

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Homework Help Overview

The discussion revolves around the definition of work in physics, particularly contrasting mechanical work and thermodynamic work. The original poster expresses confusion regarding the application of these definitions to the concept of free gas expansion, where work is stated to be zero despite the presence of pressure and expansion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of work, questioning the apparent contradiction between mechanical work and thermodynamic work in the context of free expansion. There are discussions about the role of resistive forces and the implications of different definitions on understanding work.

Discussion Status

Some participants have provided clarifications regarding the definitions of work and the conditions under which they apply, particularly in relation to free expansion. The conversation reflects a mix of interpretations and attempts to reconcile different definitions without reaching a definitive consensus.

Contextual Notes

There is an ongoing debate about the definitions of work as presented in different textbooks, and how these definitions apply to scenarios involving resistance and expansion. The original poster is grappling with the implications of these definitions on their understanding of work in thermodynamics.

shamanblues
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Hi all,

I m having a little problem with the definition of work:

-Mechanical work is a force applied through a distance, defined mathematically as the line integral of a scalar product of force and displacement vectors. Work is a scalar quantity which can be positive or negative.

-In thermodynamics, thermodynamic work is the quantity of energy transferred from one system to another. It is a generalization of the concept of mechanical work in mechanics.

----->now my real problem comes when i take free gas expansion as an example:normaly work should be equal to 0 (thats what i read in books)
How can that be since we have an expansion DV and obviously a force responsible for that expansion P (pressure).
In my book it says that work in tha case of free expansion equals to 0 because it defines work as:

-distance * force resisting to the movement.

In that case i agree that free gas expansion work equals 0 since there is nothing resisting the expansion, however that third definition is in contradiction with the first one.

I am so confused.Please help!
 
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shamanblues said:
Hi all,

I m having a little problem with the definition of work:

-Mechanical work is a force applied through a distance, defined mathematically as the line integral of a scalar product of force and displacement vectors. Work is a scalar quantity which can be positive or negative.

-In thermodynamics, thermodynamic work is the quantity of energy transferred from one system to another. It is a generalization of the concept of mechanical work in mechanics.

----->now my real problem comes when i take free gas expansion as an example:normaly work should be equal to 0 (thats what i read in books)
How can that be since we have an expansion DV and obviously a force responsible for that expansion P (pressure).
No, there is no force or pressure in free expansion. Pressure is is the force (divided by area) of the wall or membrane that prevents free expansion. Remove the barrier and the expansion happens as a consequence of the random motion of the molecules making up the gas.

In my book it says that work in tha case of free expansion equals to 0 because it defines work as:

-distance * force resisting to the movement.

In that case i agree that free gas expansion work equals 0 since there is nothing resisting the expansion, however that third definition is in contradiction with the first one.

I am so confused.Please help!
 
indeed..! now i understand better.
one more question however:

What should i learn:
-work=force*distance (my last year book) or
-work=distance*force resisting to the movement (this years book..)

...or is it quantitatively (EXACTLY (?)) the same since if there is little resistance, distance will be longer and if the resistance is greater, distance will be shorter for the same force applied?
 
Last edited:
shamanblues said:
What should i learn:
-work=force*distance (my last year book) or
-work=distance*force resisting to the movement (this years book..)

...or is it quantitatively (EXACTLY (?)) the same since if there is little resistance, distance will be longer and if the reistance is greater, diastance will be shorter for the same force applied?

To be fair, they are the same, just probably not explained to you in properly. The one you want to learn is the second one because unless you are in a vaccuum, there will always be a resistive force (normally in the opposite direction to motion).

The Bob (2004 ©
 
You have to consider the work done by the expanding gas. So if the gas expands by applying a force against something, say a piston, energy is removed from the gas in doing work on another system.
 
As long as an object is not accelerating, the net force is 0 so the "resistive force" is the same as the force applied to the object.
If the object is accelerating, then the work done by the force goes part into overcoming the resistive force and part into increasing the kinetic energy.
 
All of your replies were so helpful !
Thank you! I understand better now.

(could you please get all together and write a book!
Seriously, i got more out of your 4 posts than i did reading my whole thermodynamics chapter...)
 

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