Elroy
- 42
- 9
Alright, I'm still on the idea of straightforward (and visual) explanations of the violations of Bell's inequalities, and how they illustrate the quantum weirdness. I'm going to lay out some pieces here, and open them up to discussion.
Bell’s inequality is often stated as
ρ(a,c) – ρ(b,a) – ρ(b,c) ≤ 1,
where the ρ (rho) values are correlations between events. However, this inequality can be stated in a somewhat simpler form as a straightforward probability problem. Let’s say we have a coin. (We’ll talk a bit later about whether or not it matters that it’s “fair”.) We’ll let “tails” represent a ZERO (0), and “heads” represent a ONE (1). Furthermore, let’s assume that we’re going to flip it three times. The following table provides all the possible (eight) outcomes:
We will assume that the event we are interested in is “heads” (a ONE). Let’s identify Flip#1 as event “a”. We will also call Flip#2 event “b”, and Flip #3 event “c”. Furthermore, I’ll use the exclamation point (!) to indicate a “NOT”, such that !b would indicate the NOT b event (or that b didn’t happen, or that we didn’t get heads). I will also use the ∧ symbol to denote a boolean AND. This simply means that both events happened.
Now, I’d like to define three separate possible outcomes for our three flip events:
Outcome#1: a ∧ !b (a happened, b did not happen, and c doesn’t matter)
Outcome#2: b ∧ !c (b happened, c did not happen, and a doesn’t matter)
Outcome#3: a ∧ !c (a happened, c did not happen, and b doesn’t matter)
Let’s go back to the above table of possibilities. We find that the outcomes are identified as:
We can now imagine a situation where we do this three-coin-flip experiment over and over, each time flipping the coin three times. We count (N) how many times each of our outcomes of interest occur, recognizing (according to the above table) that there will be occasions where more than one outcome happens during a single three-flip experiment. With this information, we can state the following inequalities:
N(a ∧ !b) + N(b ∧ !c) ≥ N(a ∧ !c)
(Be sure to think this through. If we trust probability theory, and common sense, this has to be true.)
This is self-evident by the fact that (a ∧ !c) cannot occur unless either (a ∧ !b) or (b ∧ !c) also occurs. It’s straightforward to turn each term in the above inequality into a proportion, by simply dividing by the overall N (number of times we did the experiment). This transforms the inequality into:
p(a ∧ !b) + p(b ∧ !c) ≥ p(a ∧ !c)
This is actually one form of Bell’s inequality, and I hope everyone is somewhat comfortable with the above outlined arguments. Now, I want to extend this argument to something we can rather easily generalized to randomly linearly polarized photons. (For this argument, let’s ignore the cases of circular and elliptical polarization, but just FYI, they do not invalidate any of the arguments.) We might say that our photons are being emitted one-at-a-time from some emitter in direction z, and that they are randomly (linearly) polarized at some angle in the x,y plane, the plane is orthogonal (normal) to the direction of progression (z).
For visualization, let’s say we have a magic (golden) disk that emits brass bars (at the speed of light, if you like) once a second at random angles (orthogonal to progression):
https://lh3.googleusercontent.com/JCEqWeKxz5W4mS64Hubphrn7PATHAYULJS2WPs0pC6vyHFS8yCaJHguxUtNL86xjtZngJpA9aCA=w1709-h719 https://lh6.googleusercontent.com/xXmIk1ydQSSRMJlje6h1S489_pb3yaHjOB3MauhyhXwX3w4QtnNRaS6-QuQmy5rMKZznGdeRlmI=w1709-h719 https://lh4.googleusercontent.com/y-cyBHA72zR2GqNHAfua1GZYIgo_iQ3SXQM1bS5Caw2nUSi1ATcAenTWq6E45MtRUCZeJlAOXkA=w1709-h719
Let’s further assume that we have three “events” (a, b, and c) that we wish to test (very much like flipping our coin. We would like to “test” whether or not our bar passes these events. When placed orthogonal to the angle of progression, we would like to see if our brass bars will pass through disks that look like one or more of the following:
https://lh4.googleusercontent.com/EJVCSCTZqMungEtfWQGIzYuvYXadaQUCeBNlLXvHIOYo5WTwbu9RFTNhPlxxD8Bmoo0i91Wa9Yw=w1709-h719
https://lh4.googleusercontent.com/ibJ3BxDSeWGjDdDBAgNtWxLkblDA0qfprFyYnVbEDxH-KeAShTrf2cVbr6lHr5fbrrgjBt9VSpU=w1709-h719
https://lh5.googleusercontent.com/kGqgB-rOWOUBUieVsAWRVbfpOlP5wtpuSAzX3zlsegGcN7hgwECtqMy9XW3eIY_c8b5byg3hrnI=w1709-h719
The following is an example of the copper rod passing test a (where the z axis is now pointing directly into the picture).
https://lh3.googleusercontent.com/QKwuUMu5RCpqZeUXJXdVWW86K9EK1392URjgZj5rWWMqOveygqTrb4XCGGdGCrR7AqN8H-UO4r0=w1709-h719
Now, to illustrate Bell’s inequality, we can stack our tests, and we’d have something like the following:
https://lh4.googleusercontent.com/YelJ6_aKUfjaMhlr4ejLn6mxvz45PbHGrvDjT_BEhm3k_xbfKdpimBojApk_kwNbcymax0Acr2s=w1709-h7199
We can now imagine an emitted rod that passes a (red) but fails (bumps into) b (green). If the rods are randomly “polarized”, then the proportion of the time that will happen is the area of green we can see compared to the entire circle. This works out to be a linear relationship. It is simply the difference in angle between event a and event b, which is 22.5°, divided by 360°. This works out to be .0625. So, outcome#1 will happen about 6.25% of the time.
We can also work out outcome#2, (b ∧ !c) and not caring about a:
https://lh4.googleusercontent.com/3j848Uwfe9Lv5MdZtdhxx3SONjlDYQvk1BtAsd3iuhEu9pV85QKYxcmwssOg4kRnxrUU9U1IbPI=w1709-h719
This is also a 22.5° difference, which will also happen about 6.25% of the time.
Therefore, returning to Bell’s inequality, outcome#3 cannot happen more than 12.5% of the time.
Bell’s inequality:
p(a ∧ !b) + p(b ∧ !c) ≥ p(a ∧ !c)
.0625 + .0625 ≥ p(a ∧ !c)
.125 ≥ p(a ∧ !c)
Now, let’s look at the (a ∧ !c) situation with our disks (outcome#3):
https://lh5.googleusercontent.com/yxrbGCA23TLMbsmRF9ou3ZsslxtGKP6gexh54NHpBBScj6djp_mMfvg4yrqAnk5O-UC81JG2gYM=w1709-h719
This time, the “exposed” blue (c) area represents a 45° difference in the disks. 45°/360° = .125, just exactly on the border of still being within Bell’s inequality. In fact, it’s the equality version of Bell’s inequality.
Therefore, according to everything I’ve presented, Bell’s inequality holds.
I’ll stop here until another post, but I can absolutely tell you that a randomly linearly polarized photon will get through event a .5 proportion of the time, and a photon will get through event b after getting through event a .1464 proportion of the time (sin2(22.5°) ). Multiplying these together (.5 × .1464) we determine that .0732 is the proportion of observing outcome#1.
The same logic can be worked out for outcome#2 (occurring .0732 proportion of the time) while ignoring event a altogether.
Now this is where things get interesting. Still using photons, it can be shown that outcome#3 (a ∧ !c) will occur with a proportion of .25. We work this out with the knowledge that the photon will get through test a with a .5 proportion. After passing a, it will get through c .5 proportion of the time (sin2(45°)). Multiplying these together, we get .5 × .5 = .25.
Plugging these into Bell’s inequality, we get:
p(a ∧ !b) + p(b ∧ !c) ≥ p(a ∧ !c)
.0732 + .0732 ≥ .25, which is NOT correct. Bell’s inequality is violated.
I’ll explain this more in a subsequent post if there are interesting posts by others. It should be recognized that this does NOT involve EPR pairs. It is a single photon experiment that illustrates a violation in Bell’s inequality in the quantum world.
There is a fairly straightforward “loophole” that people have used to attempt to explain this violation. Can anyone explain it? I’ll give a tip. It has to do with distinctions in what happens with measurements in the classical world versus the quantum world. If interested, I’ll explain it.
And, if interested, I'll carry these explanations forward into the EPR experiments that conclusively show that local causality (locality), even when allowed to travel at the speed of light, can not explain empirically observed quantum phenomenon.
Bell’s inequality is often stated as
ρ(a,c) – ρ(b,a) – ρ(b,c) ≤ 1,
where the ρ (rho) values are correlations between events. However, this inequality can be stated in a somewhat simpler form as a straightforward probability problem. Let’s say we have a coin. (We’ll talk a bit later about whether or not it matters that it’s “fair”.) We’ll let “tails” represent a ZERO (0), and “heads” represent a ONE (1). Furthermore, let’s assume that we’re going to flip it three times. The following table provides all the possible (eight) outcomes:
Code:
Flip#1(a) Flip#2(b) Flip#3(c)
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
Now, I’d like to define three separate possible outcomes for our three flip events:
Outcome#1: a ∧ !b (a happened, b did not happen, and c doesn’t matter)
Outcome#2: b ∧ !c (b happened, c did not happen, and a doesn’t matter)
Outcome#3: a ∧ !c (a happened, c did not happen, and b doesn’t matter)
Let’s go back to the above table of possibilities. We find that the outcomes are identified as:
Code:
(a) (b) (c) Outcome#1 Outcome#2 Outcome#3
0 0 0
0 0 1
0 1 0 *
0 1 1
1 0 0 * *
1 0 1 *
1 1 0 * *
1 1 1
N(a ∧ !b) + N(b ∧ !c) ≥ N(a ∧ !c)
(Be sure to think this through. If we trust probability theory, and common sense, this has to be true.)
This is self-evident by the fact that (a ∧ !c) cannot occur unless either (a ∧ !b) or (b ∧ !c) also occurs. It’s straightforward to turn each term in the above inequality into a proportion, by simply dividing by the overall N (number of times we did the experiment). This transforms the inequality into:
p(a ∧ !b) + p(b ∧ !c) ≥ p(a ∧ !c)
This is actually one form of Bell’s inequality, and I hope everyone is somewhat comfortable with the above outlined arguments. Now, I want to extend this argument to something we can rather easily generalized to randomly linearly polarized photons. (For this argument, let’s ignore the cases of circular and elliptical polarization, but just FYI, they do not invalidate any of the arguments.) We might say that our photons are being emitted one-at-a-time from some emitter in direction z, and that they are randomly (linearly) polarized at some angle in the x,y plane, the plane is orthogonal (normal) to the direction of progression (z).
For visualization, let’s say we have a magic (golden) disk that emits brass bars (at the speed of light, if you like) once a second at random angles (orthogonal to progression):
https://lh3.googleusercontent.com/JCEqWeKxz5W4mS64Hubphrn7PATHAYULJS2WPs0pC6vyHFS8yCaJHguxUtNL86xjtZngJpA9aCA=w1709-h719 https://lh6.googleusercontent.com/xXmIk1ydQSSRMJlje6h1S489_pb3yaHjOB3MauhyhXwX3w4QtnNRaS6-QuQmy5rMKZznGdeRlmI=w1709-h719 https://lh4.googleusercontent.com/y-cyBHA72zR2GqNHAfua1GZYIgo_iQ3SXQM1bS5Caw2nUSi1ATcAenTWq6E45MtRUCZeJlAOXkA=w1709-h719
Let’s further assume that we have three “events” (a, b, and c) that we wish to test (very much like flipping our coin. We would like to “test” whether or not our bar passes these events. When placed orthogonal to the angle of progression, we would like to see if our brass bars will pass through disks that look like one or more of the following:
https://lh4.googleusercontent.com/EJVCSCTZqMungEtfWQGIzYuvYXadaQUCeBNlLXvHIOYo5WTwbu9RFTNhPlxxD8Bmoo0i91Wa9Yw=w1709-h719
https://lh4.googleusercontent.com/ibJ3BxDSeWGjDdDBAgNtWxLkblDA0qfprFyYnVbEDxH-KeAShTrf2cVbr6lHr5fbrrgjBt9VSpU=w1709-h719
https://lh5.googleusercontent.com/kGqgB-rOWOUBUieVsAWRVbfpOlP5wtpuSAzX3zlsegGcN7hgwECtqMy9XW3eIY_c8b5byg3hrnI=w1709-h719
The following is an example of the copper rod passing test a (where the z axis is now pointing directly into the picture).
https://lh3.googleusercontent.com/QKwuUMu5RCpqZeUXJXdVWW86K9EK1392URjgZj5rWWMqOveygqTrb4XCGGdGCrR7AqN8H-UO4r0=w1709-h719
Now, to illustrate Bell’s inequality, we can stack our tests, and we’d have something like the following:
https://lh4.googleusercontent.com/YelJ6_aKUfjaMhlr4ejLn6mxvz45PbHGrvDjT_BEhm3k_xbfKdpimBojApk_kwNbcymax0Acr2s=w1709-h7199
We can now imagine an emitted rod that passes a (red) but fails (bumps into) b (green). If the rods are randomly “polarized”, then the proportion of the time that will happen is the area of green we can see compared to the entire circle. This works out to be a linear relationship. It is simply the difference in angle between event a and event b, which is 22.5°, divided by 360°. This works out to be .0625. So, outcome#1 will happen about 6.25% of the time.
We can also work out outcome#2, (b ∧ !c) and not caring about a:
https://lh4.googleusercontent.com/3j848Uwfe9Lv5MdZtdhxx3SONjlDYQvk1BtAsd3iuhEu9pV85QKYxcmwssOg4kRnxrUU9U1IbPI=w1709-h719
This is also a 22.5° difference, which will also happen about 6.25% of the time.
Therefore, returning to Bell’s inequality, outcome#3 cannot happen more than 12.5% of the time.
Bell’s inequality:
p(a ∧ !b) + p(b ∧ !c) ≥ p(a ∧ !c)
.0625 + .0625 ≥ p(a ∧ !c)
.125 ≥ p(a ∧ !c)
Now, let’s look at the (a ∧ !c) situation with our disks (outcome#3):
https://lh5.googleusercontent.com/yxrbGCA23TLMbsmRF9ou3ZsslxtGKP6gexh54NHpBBScj6djp_mMfvg4yrqAnk5O-UC81JG2gYM=w1709-h719
This time, the “exposed” blue (c) area represents a 45° difference in the disks. 45°/360° = .125, just exactly on the border of still being within Bell’s inequality. In fact, it’s the equality version of Bell’s inequality.
Therefore, according to everything I’ve presented, Bell’s inequality holds.
I’ll stop here until another post, but I can absolutely tell you that a randomly linearly polarized photon will get through event a .5 proportion of the time, and a photon will get through event b after getting through event a .1464 proportion of the time (sin2(22.5°) ). Multiplying these together (.5 × .1464) we determine that .0732 is the proportion of observing outcome#1.
The same logic can be worked out for outcome#2 (occurring .0732 proportion of the time) while ignoring event a altogether.
Now this is where things get interesting. Still using photons, it can be shown that outcome#3 (a ∧ !c) will occur with a proportion of .25. We work this out with the knowledge that the photon will get through test a with a .5 proportion. After passing a, it will get through c .5 proportion of the time (sin2(45°)). Multiplying these together, we get .5 × .5 = .25.
Plugging these into Bell’s inequality, we get:
p(a ∧ !b) + p(b ∧ !c) ≥ p(a ∧ !c)
.0732 + .0732 ≥ .25, which is NOT correct. Bell’s inequality is violated.
I’ll explain this more in a subsequent post if there are interesting posts by others. It should be recognized that this does NOT involve EPR pairs. It is a single photon experiment that illustrates a violation in Bell’s inequality in the quantum world.
There is a fairly straightforward “loophole” that people have used to attempt to explain this violation. Can anyone explain it? I’ll give a tip. It has to do with distinctions in what happens with measurements in the classical world versus the quantum world. If interested, I’ll explain it.
And, if interested, I'll carry these explanations forward into the EPR experiments that conclusively show that local causality (locality), even when allowed to travel at the speed of light, can not explain empirically observed quantum phenomenon.
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