How High Does a Jumper Raise Their Center of Gravity?

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SUMMARY

The discussion centers on calculating the height a jumper raises their center of gravity when taking off at a velocity of 5 m/s at a 20-degree angle to the horizontal. The initial calculations for horizontal and vertical velocities were incorrectly assigned, leading to confusion. The correct vertical velocity should be calculated using Vv = 5 * cos(20), resulting in a height of 0.14 meters. The participants clarified that the angle should be interpreted as 20 degrees to the vertical for accurate calculations.

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bionut
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Homework Statement


A jumper takes off with a velocity of 5 ms at an angle of 20 degrees to the horizontal.
How high does he raise his center of gravity?



Homework Equations





The Attempt at a Solution


I know that Vh= 5scos20 = 1.7 m/s and Vv=5Csin20=4.70 m/s

using 0=Vi^2 + 2ad
0=5sin20 + 2 X-9.81d
19.62d=1.7
d=1.7/19.62
d=0.087m, but its incorrect. Am I misssing something? The only Thing I can think of is beacuse its his centre of gravity that I should treat it as a vertical launnched projectile?
 
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bionut said:

Homework Statement


A jumper takes off with a velocity of 5 ms at an angle of 20 degrees to the horizontal.
How high does he raise his center of gravity?



Homework Equations





The Attempt at a Solution


I know that Vh= 5sin20 = 1.7 m/s and Vv=5Cos20=4.70 m/s

using 0=Vi^2 + 2ad
0=5sin20 + 2 X-9.81d
19.62d=1.7
d=1.7/19.62
d=0.087m, but its incorrect. Am I misssing something? The only Thing I can think of is beacuse its his centre of gravity that I should treat it as a vertical launnched projectile?

Nothing wrong with your calculation. Since they are asking how high, could this be the high-jump and the angle is actually 20 degrees to the vertical?
 
thanks for your help, that's what i was thinking would it then mean that the Vv is 5Cos20 instead of 5Sin20? Is that what you are suggesting?, also the answer is 0.14m...
 
Can anyone else help... I still can't get 0.14m?

:-(
 

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