Projectile locust jump question

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SUMMARY

Locusts can jump up to 75 cm on a level surface, launching at an angle of 55 degrees. To determine the initial velocity of the locust, one must analyze the components of the jump using projectile motion equations. The horizontal distance can be described using the formula \(d = v_x \cdot t\), where \(v_x\) is the initial horizontal velocity and \(t\) is the time of flight. The time of flight can be calculated from the initial vertical velocity and the acceleration due to gravity.

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  • Understanding of projectile motion principles
  • Familiarity with trigonometric functions for angle decomposition
  • Knowledge of kinematic equations
  • Basic grasp of gravitational acceleration (9.81 m/s²)
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Large insects such as Locusts can jump as far as 75 cm. on a level surface. an entomologist analyzed a photograph and found that the insects's launch was at an angle of 55.
What was the initial velocity of the insect?

those are the only givens I am given... how do i figure this one out? Even a small hint would be appreciated :-D
 
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Having the initial angle is quite a lot. From that you can identify the initial x and y velocity components. That is a good place to start.

What formula can describe the distance observed in the x direction? And how might you calculate the time of flight from initial y velocity and knowing gravity acts at a constant rate?
 

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