- #1

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- Thread starter Towk667
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- #1

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- #2

- 87

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you can then work backwards to find theta.

start with splitting the initial velocity into orthogonal components.

- #3

LowlyPion

Homework Helper

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These equations might be a useful resource for you:

https://www.physicsforums.com/showpost.php?p=905663&postcount=2

- #4

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- #5

LowlyPion

Homework Helper

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Typically the trig identity

2*sinθ*cosθ = sin2θ

is of use in resolving Range equations.

Without seeing your work, there's no useful way to help you with what you are doing that I can see.

- #6

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or just remember that sin(x)/cos(x) = tan(x)

edit: yeah or the trig identity posted above

- #7

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I tried to solve this equation for Θ and get:

(gR)/(V0^{2})=.5sin2Θ+sqrt(sin^{2}Θ+((2gh)/V0))

Am I using the wrong equation or there another trig identity or what?

- #8

- 127

- 3

{[ucosӨ * sqrt(u^2sin^2Ө + 2gh)] +[2u^2sin2Ө]}/2g = R

I don't know what to do ahead of this, but I'm quite sure this is the correct equation.

- #9

- 127

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"What is the average velocity of a projectile between the instants it crosses half the maximum height? It is projected with a speed 'u' at an angle Ө with the horizontal"

(a) u sinӨ (b) u cosӨ (c) u tanӨ (d) u

Could I get some help on this one? I don't even know where to start.

- #10

- 17

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"What is the average velocity of a projectile between the instants it crosses half the maximum height? It is projected with a speed 'u' at an angle Ө with the horizontal"

(a) u sinӨ (b) u cosӨ (c) u tanӨ (d) u

Could I get some help on this one? I don't even know where to start.

I think I can help with this one. Think about the formula to find maximum height and then use that knowledge and a formula for final velocity that doesn't use time to get your answer.

- #11

- 127

- 3

I think I can help with this one. Think about the formula to find maximum height and then use that knowledge and a formula for final velocity that doesn't use time to get your answer.

I did what you said and got the following equation for the final velocity:

sqrt{ [ (2g (u sinӨ)^2) + (2g (u cosӨ)^2) - ((u sinӨ)^2)] / 2g }

Now, what do I do? I don't think I can use the final velocity to evaluete the average velocity, right?

Is there any other method in which I can find the total distance and total time?

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