(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A Hollywood daredevil plans to jump the canyon shown in the figure on a motorcycle. There is a 15. m drop and the horizontal distance originally planned was 60. m but it turns out the canyon is really 69.4 m across. If he desires a 3.0-second flight time, what is the correct angle for his launch ramp (deg)?

2. Relevant equations

vx = vxo

x − xo = (vox)t

(vy) = (vyo) − gt

y − yo = (voy)t −(1/2)g t^2

Range =((vo^2)/g) sin(2θ)

3. The attempt at a solution

x − xo = (vox)t

69.4m = (vox)(3s)

23.13 m/s = vox

Range =((vo^2)/g) sin(2θ)

69.4m ={ (23.13^2 m/s)/9.81 m/s^2 } sin(2θ)

θ = error

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# Homework Help: Projectile Motion: Finding the correct angle for a launch

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