Projectile Motion Homework Help: Solving Launch and Landing Problems

Click For Summary
SUMMARY

The discussion focuses on solving projectile motion problems involving launch angles and initial velocities. The first problem requires calculating the initial velocity for a ball launched at 60 degrees to reach a helicopter 110 feet away and 90 feet high, using the equations 90 = viT + 0.5aT^2 and 90 = vi(cos60)T. The second problem involves finding two angles for a ball launched with an initial velocity of 38 m/s that lands 29 meters away. Participants emphasize the separation of x and y components in projectile motion equations and the need to solve for one variable before substituting it into the other equation.

PREREQUISITES
  • Understanding of projectile motion equations
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of kinematic equations in physics
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation of projectile motion equations
  • Learn how to decompose vectors into their x and y components
  • Explore the use of kinematic equations in two dimensions
  • Investigate the effects of launch angle on projectile range and height
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone seeking to improve their problem-solving skills in kinematics.

nando94
Messages
33
Reaction score
0
Stuck on these homework problems.

1. A ball is launched 60 degrees above the x-axis to a helicopter that is 110 feet away and 90 feet high. What is the initial velocity required to reach it?

I know the equation we have to use is

90 = viT + .5aT^2

and that 90 = vi(cos60)T


2. Another ball is launched with an initial velocity of 38 m/s and lands 29 meters away. Find the two angles that meet this.

would you use the same equations?
 
Physics news on Phys.org
nando94 said:
Stuck on these homework problems.

1. A ball is launched 60 degrees above the x-axis to a helicopter that is 110 feet away and 90 feet high. What is the initial velocity required to reach it?

I know the equation we have to use is

90 = viT + .5aT^2

and that 90 = vi(cos60)T

Keep in mind that x and y are separate.
So you know that in time T the ball must travel 110 feet in the x direction and 90 feet in the y direction.

Your equations are close, but v_i in the first equation should only be the y component of v_i.
the second equation is for the x direction, so you should have 110 feet, not 90.

But otherwise, looks solid. Now, since you have 2 equations and 2 unknowns, you have to solve for one variable and then substitute it into the other equation. (Try solving the second equation for T and going from there)


Not sure about #2. Seems you have 3 unknowns (y, t and angle).
 

Similar threads

Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
27K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
19
Views
3K
Replies
25
Views
3K