A rifle is used to fire two bullets. The first shot is at an angle of 60° above the horizontal and the second at an angle of 45° above the horizontal. The speed of EACH bullet as it leaves the rifle is 200ms^1. For EACH bullet calculate the horizontal range and the corresponding time of flight.
Horizontal Range: v^2sin2ө/ g
Time of Flight= 2vsinө/g
The Attempt at a Solution
Horizontal Range for 1st shot= (200^2)sin2(60)/9.81
Time of Flight= 2(200)sin(60)/9.81
Horizontal Range for 2nd shot= (200^2)sin2(45)/9.81
Time of Flight= 2(200)sin(45)/9.81
= 28.8 secs
I'm not sure if I'm supposed to use the 200 as v or if I'm to calculate v somehow from the given information.