1. The problem statement, all variables and given/known data A rifle is used to fire two bullets. The first shot is at an angle of 60° above the horizontal and the second at an angle of 45° above the horizontal. The speed of EACH bullet as it leaves the rifle is 200ms^1. For EACH bullet calculate the horizontal range and the corresponding time of flight. 2. Relevant equations Horizontal Range: v^2sin2ө/ g Time of Flight= 2vsinө/g 3. The attempt at a solution Horizontal Range for 1st shot= (200^2)sin2(60)/9.81 =3531m Time of Flight= 2(200)sin(60)/9.81 =35.3 secs Horizontal Range for 2nd shot= (200^2)sin2(45)/9.81 =4077m Time of Flight= 2(200)sin(45)/9.81 = 28.8 secs I'm not sure if I'm supposed to use the 200 as v or if I'm to calculate v somehow from the given information.