Projectile motion in a spring loaded gun

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SUMMARY

The discussion centers on calculating the number of turns (N) in a helical spring for a Turbo Booster toy that launches a 60-gram glider projectile. The spring is made of carbon steel wire with a diameter of 1.1 mm and a coil diameter of 10 mm. Using the conservation of energy, the spring constant (k) can be derived from the formula k = (d^4 * G) / (8D^3 * N), where G is the shear modulus (11.2 x 10^6 psi). The total working deflection is 150 mm, and the projectile is expected to ascend approximately 8 m before falling.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Familiarity with helical spring mechanics
  • Knowledge of shear modulus and its application
  • Basic skills in algebra for solving equations
NEXT STEPS
  • Calculate the spring constant (k) using the provided formula
  • Determine the number of turns (N) required for the spring
  • Explore the relationship between wire diameter and spring performance
  • Review Shigley's Mechanical Engineering Design for detailed spring calculations
USEFUL FOR

Students in physics or mechanical engineering, hobbyists designing spring-loaded devices, and anyone interested in the mechanics of projectile motion.

Darknes51986
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Homework Statement


1. A Turbo Booster toy that launches a 60-gram “insect” glider projectile by compressing a helical spring and then releasing the spring when the trigger is pulled. When pointed upward the glider should ascend approximately 8 m before falling. The launcher is made with carbon steel wire, with a diameter of d=1.1 mm. The coil diameter is D=10 mm. Calculate the number of turns N in the spring such that it would provide the necessary energy to the glider. The total working deflection is x=150 mm with a clash allowance of 10%.

Homework Equations


I need to used conservation of energy to find initial velocity and spring constant I believe. Final velocity is 0. Not sure how to find the number of turns in the spring though.

KE=1/2*m*V^2
PE=m*g*h

The Attempt at a Solution



g=9.81 m/s^2 gravity
d=1.1 mm wire diameter
D=10 mm col diameter
m=60 gm mass of toy
x=150 mm working deflection
dist= 8 m distance traveled

C=D/d=10/1.1= 9.091 spring index
G=11.2*10^6 psi (for carbon steel)
k=?
V=?

somehow need number of turns
 
Last edited:
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trying to bump this up
 
This looks like it's outside the scope of a standard introductory physics class, which normally does not discuss how the number of turns and wire diameter related to the spring constant.

I am wondering if your professor has given you additional material on this?

At any rate, it is possible to find the spring constant k using conservation of energy methods.
 
This is definitely a combination of physics and mechanical design. You have the correct approach. Conservation of energy will allow you to calculate the spring constant needed to impart the correct amount of energy needed to reach 8 m. From here, you can use the equation for the spring constant of a helical spring (as obtained from Shigley's Chapter 10-3)
k = \frac{d^4 G}{8D^3 N}
Where d is the wire diameter, D is the mean spring diameter, G is the shear modulus of the material, and N is the...tada, number of turns in the spring.

Good luck,

p.s. tex is still down, so try to read this for the spring constant
k = (d^4 * G) / (8D^3 N)
 

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