1. The problem statement A child runs down a hill with an angle of 20 degrees and then jumps up at a 20 degree angle above the horizontal. He lands 2.2m down the hill as measured along the hill. What is the child's initial velocity? 3. The attempt at a solution Okay, I'm not even sure if I have my initial measurements right. This is a projectile problem right? With initial velocity unknown and a 40 degree angle (measured against the ground). So, first I tried to find the time needed using Vxf=Vx0 + at. -V0sin40 = Vosin40 - 9.8t t= 2Vosin40/9.8 Then, i plug that into the Dy=Vy*t 2.2=(Vcos40)(2Vosin40 / 9.8) 10.78 = v^2 * cos40sin40 v=4.68m/s I tried that answer, but it isn;t correct. What am i doing wrong?