Okay I know this should be easy but for some reason I just cant get it. "You throw a ball toward a wall with a speed of 25.0 m/s and at an angle of 40.0 degrees above the horizontal. The wall is 22.0 m from the release point of the ball. (a) How far above the release point does the ball hit the wall? (b) What are the horizontal and vertical components of its velocity as it hits the wall? (c) When it hits, has it passed the highest point on its trajectory?" A friend told me to use Vy=25sin(40) = 16.07 but I'm not sure what that's for. I found that the ball hits the wall after .88 seconds, and I think the height of the wall might be 18.46 m but I'm not sure. I think I'm just confused about equations, vertical/horizontal components, and magnitude. Okay that's actually alot :[ Thank you!