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Projectile motion problem (can someone check my work?)

  1. Oct 21, 2016 #1
    1. The problem statement, all variables and given/known data
    A ball is hit at a height of 1.00 m above ground such that it barely clears a wall that is 21.0 m high. This wall is located 130 m away from the location that the ball was hit (home plate). The ball was hit an angle that is 30° with respect to the horizontal. Find the following quantities:

    a) The time it takes the ball to reach the wall.
    b) The initial speed of the ball after it is hit.
    c) The speed of the ball when it reaches the wall.

    2. Relevant equations
    See below

    3. The attempt at a solution
    20161021_174031.jpg

    Can someone check my work?
     
  2. jcsd
  3. Oct 21, 2016 #2

    kuruman

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    Your starting premise is incorrect and this invalidates the rest of your work. You say
    ## v_y^2=v_{0y}^2+2a\Delta x ##. This is OK except that you should have used ##\Delta y## instead. Most importantly, the next equation is unjustified. You say ##0=v_{0y}^2+2a\Delta x ##. Why is ##v_y = 0##? "Barely clears the wall" doesn't mean that the ball clears the wall when it is at maximum height. Also you replace the acceleration with +9.8 m/s2. It should be negative. That's for starters.

    You need to write an equation that gives the height of the ball above ground at any time t, then say that at specific time tf (time of flight) the ball is at height 21 m and solve that equation for tf. At some point you should use that in the same time tf the ball has traveled 130 m horizontally.
     
  4. Oct 21, 2016 #3
    Couldn't "Barely clears the wall" mean three different things?

    20161021_183546.jpg

    Wouldn't the ball barely clear the wall in all three scenarios depicted above where a, b, or c is equal to 130 m and h is equal to 20 m? Is this problem ambiguous in meaning? What qualifies one of the three scenarios over the other two?

    I did mean delta y, but wrote x instead. I used the value for delta y for the calculation.
     
  5. Oct 21, 2016 #4
    The three situations you show in the previous post are all possibilities - but not for the specific conditions of this problem. For this problem, only one of those will be true. For the distances specified in this problem, I strongly suspect that this problem will be case (c). But working the problem out will let you know for sure.
     
  6. Oct 21, 2016 #5
    I still don't understand how not all of the three situations are possible.

    The truth is, this question was on a midterm I just took. When I read the question, I immediately thought that "barely clearing the wall" meant that the maximum height of the projectile was the height of the wall. Do I have any standing to argue that my interpretation of the question is valid?
     
  7. Oct 21, 2016 #6
    If the angle of the initial velocity, the vertical distance to the wall, and the horizontal distance to the wall are all specified, then it is true that only one of those cases is possible. Even in your picture, you changed the wall height and horizontal distance to create the three cases - for a given angle, θ, and given initial velocity. In your original problem, you are given a specific wall height, initial velocity angle, and horizontal distance. Try to create the 3 cases for those parameters to see it you can make it work.
     
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