Projectile Motion: Solving for Range at Various Launch Angles

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Homework Help Overview

The original poster presents a problem involving projectile motion, specifically calculating the range of a shot put thrown at various launch angles from a specified height. The initial speed and height are provided, and the angles of interest are 20, 30, and 40 degrees.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to solve for the time of flight using the vertical motion equation and then applies that time to find the horizontal range. Some participants question the use of height in feet versus meters, suggesting that this may affect the calculations.

Discussion Status

Participants are engaging with the problem, noting potential issues with unit conversion related to the initial height. There is an acknowledgment of the original poster's approach, but no consensus has been reached on the correctness of the calculations.

Contextual Notes

The problem involves a mix of units (feet for height and meters for speed), which may be a source of confusion. The original poster's calculations are based on the assumption that all values are in compatible units.

ama
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Homework Statement


A shot-putter throws the shot with an initial speed of 4.0 m/s from a height of 4.5 ft above the ground. Calculate the range of the shot for each of the following launch angles.
a. 20 degrees
b. 30 degrees
c. 40 degrees
Vo=4
yo=4.5

Homework Equations


y = yo + Vo*sinθ*t - 1/2*g*t^2.
x = Vo*cosθ*t.

The Attempt at a Solution


I tried solving for the time in the first equation. I was careful to put in the height 4.5 for yo since it specifies that in the problem. I then tried to plug the time value into the second value. Then I repeated it for the other angles. Here is an example of what i did.
y=(4.5)+4(sin20)(t)-(1/2)(9.81)(t^(2))
y=4.5+1.36808t-4.9t^(2)
t=1.1081
x=4(cos20)(1.1081)
x=4.16509
For 30
4.1011499
For 40
3.8483
Yet for some reason these answers are wrong. Why?
 
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ama said:
I was careful to put in the height 4.5 for yo since it specifies that in the problem.
Note that the initial height was given in feet.
 
welcome to pf!

hi ama! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)
ama said:
… from a height of 4.5 ft

y=(4.5)+4(sin20)(t)-(1/2)(9.81)(t^(2))

erm :redface:

feet! :biggrin:
 
lol. I am so really new to physics.
 

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