1. The problem statement, all variables and given/known data a stone is projected at a cliff of height h with an initial speed of 46.0 m/s directed at an angle θ0 = 65.0° above the horizontal. The stone strikes at A, 5.47 s after launching. Find (a) the height h of the cliff, (b) the speed of the stone just before impact at A, and (c) the maximum height H reached above the ground. 2. Relevant equations v0x= vcostheta v0y= vsintheta vfy= v0y-gt 3. The attempt at a solution first, i broke the vector up into components v0x= 19.44 v0y= 41.69 vfy= v0y-gt y= -1/2gt^2 +v0yt + y0 then i tried to find b) the speed of the stone i did vfy= v0y-gt and got -11.92 that was wrong i'm pretty lost when it comes to the other stuff.. please help?