Projectile motion stunt doubles

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SUMMARY

The discussion centers on calculating the necessary horizontal velocity for a car to land 90.0 m from a 50.0 m high cliff in the movie Thelma and Louise. The correct horizontal speed required is 101 km/h. Participants clarify that the time taken for the car to fall is approximately 5.1 seconds, derived from the equation of motion under gravity, where the initial vertical velocity is zero. Misunderstandings about the calculations and units were addressed, leading to a consensus on the correct approach.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Ability to convert units (e.g., m/s to km/h)
NEXT STEPS
  • Study kinematic equations for projectile motion
  • Learn how to calculate time of flight for free-falling objects
  • Explore the effects of initial velocity on projectile trajectories
  • Investigate real-world applications of projectile motion in stunt coordination
USEFUL FOR

Physics students, stunt coordinators, filmmakers, and anyone interested in the practical applications of projectile motion in cinematic stunts.

pinkfloyd12
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In the movie Thelma and Louise, the two actresses drove off a cliff at the end. In preparation for the scene, their stunt doubles determined that the cliff was 50.0 m high. The director wants the car to land 90.0 m from the base of the cliff close to the camera location. How fast must the car be traveling in order to land at this location? [101 km/h]

I found this question on the internet, I had been doing projectile questions all night with great success, however for some reason i can't seem to get 101km/hr for this question. It doesn't make sense.

If it is driven off the cliff, then inital vertical velocity is 0, therefore gravity will pull it down in 5.1 seconds no? So in that 5.1 seconds the car must have enough vertical velocity to go 90m, traveling at 17.6m/s for 5.1seconds will take you 90m.

Whats the deal? Is that answer wrong?
 
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just to clear things up how did you calculate 5.1 seconds?
 
pinkfloyd12 said:
If it is driven off the cliff, then inital vertical velocity is 0, therefore gravity will pull it down in 5.1 seconds no?


What did you use to obtain this time?
 
i can obtain the correct answer, we just need to see where you got 5.1 seconds from?
 
Welcome to PF!

Hi pinkfloyd12! Welcome to PF! :smile:
pinkfloyd12 said:
… the cliff was 50.0 m high.

If it is driven off the cliff, then inital vertical velocity is 0, therefore gravity will pull it down in 5.1 seconds no?

Noooo :wink:
 
Whoooops. Got it. Units to the maximum.
 

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