Projectile Motion : Work and Energy

Click For Summary
SUMMARY

The discussion focuses on calculating the work done on a ball by a spring in a projectile-spring launcher scenario. The user provided specific parameters: a spring displacement of 0.05m, a ball mass of 0.010kg, and an initial launch velocity of 2 m/s. The kinetic energy (KE) was calculated as 0.2J using the formula KE = 1/2mv^2, leading to the conclusion that the spring constant (k) is 160 N/m based on the relationship between kinetic energy and spring potential energy (Uspring).

PREREQUISITES
  • Understanding of kinetic energy calculations
  • Familiarity with Hooke's Law and spring constants
  • Basic knowledge of projectile motion principles
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the principles of Hooke's Law in detail
  • Learn about energy conservation in mechanical systems
  • Explore projectile motion equations and their applications
  • Investigate the effects of different spring constants on projectile motion
USEFUL FOR

Students and educators in physics, engineers working with mechanical systems, and anyone interested in the dynamics of projectile motion and energy transfer in spring systems.

ReCryptic
Messages
11
Reaction score
0
Homework Statement
Estimate the amount of work done on the ball by the spring.
Relevant Equations
Work for spring = -1/2kxf^2 + 1/2kxi^2
Kinetic Energy = 1/2mv^2
Potential Spring Energy = 1/2kx^2
The problem is based on a projectile-spring launcher. A ball is loaded into a tube that pushes back a spring and is then launched. The ball was launched straight horizontally not at an angle.

I'm trying to find the work done on the ball by the spring.

The info I have:

Displacement of spring = .05m
Mass of ball = .010kg
Initial height = 0m.
Initial velocity of ball after launch = 2 m/s.

KE = 1/2mv^2
= 1/2 * .01kg * 2m/s^2 = .2J

The spring energy is converted to Kinetic energy after launch so KE = Uspring.

KE = Uspring
.2J = 1/2kx^2
.2J = 1/2k*(.05m)^2
80 = 1/2k
k = 160 N/m.

Is my work so far correct?
 
Physics news on Phys.org
ReCryptic said:
1/2 * .01kg * 2m/s^2 = .2J
Is the decimal point misplaced?
 
Which one?
 
I figured it out can you delete the post please?
 
ReCryptic said:
I figured it out can you delete the post please?
On PF, once a post has received help, the thread is never* deleted.

* almost never
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
2
Views
2K