Projectile problem (This is a quickie)

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Homework Help Overview

The discussion revolves around a problem involving a projectile's momentum and kinetic energy, specifically how to determine the mass of the projectile given its momentum of 200 kg.m/s and kinetic energy of 1000 J. Participants are exploring the relationships between these physical quantities and the relevant equations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to derive the mass using the equations for momentum and kinetic energy. There are questions about unit consistency and the interpretation of results, particularly regarding the derived value of mass and the units of velocity.

Discussion Status

Some participants have provided clarifications regarding the units involved in the equations, while others are questioning the assumptions made in the calculations. There is an ongoing exploration of the relationships between the variables, but no consensus has been reached on the correct interpretation of the results.

Contextual Notes

There are indications of confusion regarding the units of measurement, particularly how Joules relate to Newtons and the implications for the calculations. Participants are also addressing the need for a solid understanding of fundamental equations in physics.

gcombina
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Hello, I need help on my basic math

This is the problem
A projectile is launches with 200kg.m/s of momentum and 1000 J of kinetic energy. What is the mass of the projectile.
(a) 20 kg

This is my math:

P = mv so
m = P/v
m = (200 kg.m/s)/v

KE = 1000 J
1000 J = 1/2 mv ^2
1000 J = 1/2 (mv) v
1000 J = 1/2 (200) v
v = 10 J

IF m = 200/v
m= (200 kg.m/s)/ (10 J)
m= (200 kg.m/s) / (10 NM)
m = (200 kg.m/s) / (10 ma.m)
m = (200 kg.m/s) / (10 kg.m/s.m)
m = (20/m) WHY IS THAT I HAVE THIS ANSWER?? 20/M? Instead of 20kg?
 
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Both sides of every equation has units, including this one:
1000 J = 1/2 (200) v

You wrote v = 10 J
but v does not have units of Joules.
 
gcombina said:
1000 J = 1/2 mv ^2
1000 J = 1/2 (mv) v
1000 J = 1/2 (200) v
v = 10 J
You forgot that the 200 has units of kg*m/s so when you divide Joules by kg*m/s you get m/s
So the answer is v=10 m/s

gcombina said:
m= (200 kg.m/s)/ (10 J)
m= (200 kg.m/s) / (10 NM)
m = (200 kg.m/s) / (10 ma.m)
m = (200 kg.m/s) / (10 kg.m/s.m)
m = (20/m) WHY IS THAT I HAVE THIS ANSWER?? 20/M? Instead of 20kg?

Now try it with 10 m/s instead of 10 J and see if it works out.
 
when I divide J/(kg*m/s), I get m/s? how so??

isn't J = NM?

so it would be [(nm) / (kg*m/s )] ?
 
gcombina said:
when I divide J/(kg*m/s), I get m/s? how so??

isn't J = NM?

so it would be [(nm) / (kg*m/s )] ?

Yes, and a Newton is kg*m/s^{2} so a Joule is kg*m^{2}/s^{2}
So divide kg*m^{2}/s^{2} (Joules) by kg*m/s and what do you get?
 
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gcombina said:
when I divide J/(kg*m/s), I get m/s? how so??

isn't J = NM?

so it would be [(nm) / (kg*m/s )] ?
This is where mastery and easy recall of equations is important.

W=Fs
But F=ma

So W=mas
This tels you that the Joule is a kg m m / sec2
 
@nascent Oxygen

I am sorry , I do not understand ...what is fs? what is mas?
 
@nathaneal,
thanks!
 
gcombina said:
@nascent Oxygen

I am sorry , I do not understand ...what is fs? what is mas?
These are equations you must commit to memory. They are your tools of trade.

W=F.s where F is force & s is displacement (both F and s are vectors).

F=m.a where F is force & a is acceleration (both a anf F are vectors).
 

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