Projectile Recoil: Find Gun Horizontal Speed

  • Thread starter Thread starter verden
  • Start date Start date
  • Tags Tags
    Projectile
Click For Summary

Homework Help Overview

The problem involves a gun mounted on wheels that fires a projectile, and the objective is to determine the horizontal recoil speed of the gun. The context includes concepts from momentum conservation and projectile motion, specifically focusing on the effects of firing a projectile at an angle.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum, with one attempting to relate the mass of the gun and projectile to their velocities. There is also a question about the relevance of the angle of the projectile's launch to the horizontal speed of the gun.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the need to consider the horizontal component of the projectile's velocity, but there is no explicit consensus on the correct approach or final answer.

Contextual Notes

One participant notes confusion regarding the relationship between the velocities of the gun and the projectile, particularly in relation to the Earth. There is also mention of a potential discrepancy in the calculated values based on the angle of launch.

verden
Messages
6
Reaction score
0

Homework Statement



A 1200 kg gun mounted on wheels shoots an 8.00 kg projectile with a muzzle velocity of 600 m/s at an angle of 30.0 degrees above the horizontal. Find the horizontal recoil speed of the gun.

Homework Equations



F = ma

The Attempt at a Solution



I can not find anything in the book that resembles this equation. so do not know where to start. The answer in the book is 3.46 m/s

Also does the degrees have anything to do with the equation because it asks for the horizontal speed.
 
Physics news on Phys.org
What is happening is that something is being fired and hence losing mass.

So it some initial momentum and then it loses some mass (at some velocity and hence momentum).

Hence you need to apply conservation of momentum here.
 
After checking some of the other threads figured that

1200kg x V = 8 kg x 600 m/s but that puts V at 4 m/s

am I going in the right direction

Also is this 4 m/s in relation with the 600 m/s what if I needed to solve for the bullet and the gun in relation to the Earth instead f the gun?
 
verden said:
After checking some of the other threads figured that

1200kg x V = 8 kg x 600 m/s but that puts V at 4 m/s

am I going in the right direction

Also is this 4 m/s in relation with the 600 m/s what if I needed to solve for the bullet and the gun in relation to the Earth instead f the gun?

You have the general idea down, but the velocity is at an angle of 30 degrees, so the horizontal component of velocity would be 600cos(30) m/s.
 

Similar threads

  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 6 ·
Replies
6
Views
7K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
9
Views
5K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K