Projectile with different landing height

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To solve for the total time of flight of a handball projected from a 20-meter tower at a 30-degree angle, with initial vertical and horizontal velocities of 10 m/s and 20 m/s respectively, the vertical motion equation is essential. The equation y = 20 + 10t - 4.9t^2 models the projectile's height over time, accounting for the initial height and gravitational acceleration. To find the time of flight, set the equation equal to zero and solve for t. This approach effectively addresses the differing landing height compared to a flat surface. The solution involves determining when the projectile reaches ground level from its initial height.
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Homework Statement



A handball is projected at an angle of 30 degrees with the horizontal from a 20 meter tower with an initial vertical velocity of 10 ms and an initial horizontal velocity of 20 ms. Find the total time of flight.


Homework Equations





The Attempt at a Solution



I know that 0=Vi + at will give me time up X2 will give total time for a projectile with same landing height, but what do I need to use if it has a different landing height?
 
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IIRC that's a lot more info than you need, you only need a function to describe the position of y at any given t, and solve for 0. Since they didn't give you a vector, but an explicit description of vertical velocity, this shouldn't be hard.

If your position is initially 20m, then

y = 20 +...

Your velocity is 10 m/s

y = 20 + 10t

Minus acceleration due to gravity..

y = 20 + 10t - 4.9t^2

Should describe your projectile at any t.
 
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