Projectile with different landing height

  • Thread starter Thread starter bionut
  • Start date Start date
  • Tags Tags
    Height Projectile
Click For Summary
SUMMARY

The discussion focuses on calculating the total time of flight for a handball projected from a height of 20 meters at an angle of 30 degrees. The initial vertical velocity is 10 m/s, and the initial horizontal velocity is 20 m/s. The equation of motion for the vertical position is derived as y = 20 + 10t - 4.9t², incorporating the effects of gravity. This equation allows for determining the time of flight when the projectile lands at a different height than its launch point.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Knowledge of vertical and horizontal velocity components
  • Basic grasp of gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Study the derivation of projectile motion equations
  • Learn how to apply kinematic equations to different landing heights
  • Explore the effects of launch angle on projectile trajectories
  • Investigate numerical methods for solving quadratic equations in motion problems
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone interested in applying kinematic principles to real-world scenarios.

bionut
Messages
54
Reaction score
0

Homework Statement



A handball is projected at an angle of 30 degrees with the horizontal from a 20 meter tower with an initial vertical velocity of 10 ms and an initial horizontal velocity of 20 ms. Find the total time of flight.


Homework Equations





The Attempt at a Solution



I know that 0=Vi + at will give me time up X2 will give total time for a projectile with same landing height, but what do I need to use if it has a different landing height?
 
Physics news on Phys.org
IIRC that's a lot more info than you need, you only need a function to describe the position of y at any given t, and solve for 0. Since they didn't give you a vector, but an explicit description of vertical velocity, this shouldn't be hard.

If your position is initially 20m, then

y = 20 +...

Your velocity is 10 m/s

y = 20 + 10t

Minus acceleration due to gravity..

y = 20 + 10t - 4.9t^2

Should describe your projectile at any t.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
18K
  • · Replies 15 ·
Replies
15
Views
27K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
19
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K