Projecting a point/vector onto a plane

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To project the vector a=(1,2,0,-1) onto the plane spanned by v1=(1,0,0,1) and v2=(1,1,2,0) in R4, it's essential to first confirm that a is indeed a vector. The projection involves finding a basis that includes the two spanning vectors and determining the coefficients for the linear combination that represents the projection. The process requires solving a system of equations derived from the linear combination of the basis vectors. Understanding the concept of projection in this context is crucial for correctly applying the method.
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Homework Statement


In R4 equipped with the standard inner product find the projection of a=(1,2,0,-1) on the plane
V spanned by v1=(1,0,0,1) and v2=(1,1,2,0)


Homework Equations





The Attempt at a Solution


Firstly I'm not sure if a is a point or a vector, which would surely affect the final answer.
I think I should find the normal to the plane but I'm not sure what to do with it.
Does anyone know of a formula for projection onto a plane?
I find projections really confusing so if anyone can give some guidance on how to approach problems like this one I would be really grateful.

Many thanks
 
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a is a vector, the vector extending from the point (0, 0, 0, 0) to the point (1, 2, 0, -1). It wouldn't make sense to talk of "projecting" a point onto a plane.
(The confusion is one reason I prefer to use "< >" for vectors rather than "( )".)

I think what I would do is find a basis for R4 that contains the two vectors (1,0,0,1) and (1,1,2,0). For example, if we add the vectors (0, 1, 0, 0) and (0, 0, 0, 1), we can see that a(1, 0, 0, 1)+ b(1, 1, 2, 0)+ c(0, 1, 0, 0)+ d(0, 0, 0, 1)= (a+ b, b+ c, 2b, a+ d)= (0, 0, 0, 0) then we have a+ b= 0, b+ c= 0, 2b= 0, a+ d= 0. Obviously b= 0 so a+ b= a= 0, b+ c= c= 0, and a+ d= d= 0. Since we must have a= b= c= d= 0, the four vectors are independent so form a basis for R4. Now, write (1, 2, 0, -1)=a(1, 0, 0, 1)+ b(1, 1, 2, 0)+ c(0, 1, 0, 0)+ d(0, 0, 0, 1) and solve for at least a and b. a(1, 0, 0, 1)+ b(1, 1, 2, 0) will be the projection of v on the given plane.
 
Hi HallsofIvy, thanks for your response.

I'm still quite unsure as to what a projection actually is in this context. Is there any way you could briefly explain the basic idea?

Thanks
 
haha stuck on this one too mate..
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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