Projecting push forward of a vector

In summary, the conversation discusses the diffeomorphism between two manifolds, with one being a hypersurface in the other. The use of a unit normal field and a projector is introduced, and it is shown how the pushforward of a vector and tensor can be generalized using this projector. The issue of orthogonality is raised, and it is suggested to think of the tensor in terms of tensor products of basis vectors.
  • #1
Augbrah
3
0

Homework Statement


Say we have two manifolds N(dim d) and M(dim d-1). Let Φ: M →N be a diffeomorphism where Σ = Φ[M] is hypersurface in N. Let n be unit normal field (say timelike) on Σ and ⊥ projector (in N) defined by:
[tex]⊥^a_b = \delta^a_b + n^a n_b[/tex]

Where acting on (s, 0) tensor projection operator is: [itex]⊥T^{a_1 a_2 ... a_r}=⊥^{a_1} _{b_1}...⊥^{a_s} _{b_s}T^{b_1 ... b_s}[/itex]

How to show that for a vector V at p on M, the pushforward of V satisfies: [tex]Φ_*(V)=⊥(Φ_*V)[/tex] (I can do that)

And then generalize to (s, 0) tensor: [tex]Φ_*(T)=⊥(Φ_*T)[/tex]

Homework Equations

The Attempt at a Solution


[/B]
In component form we would get: [itex] (⊥(Φ_*V))^a = ⊥^a_b (Φ_*V)^b=(\delta^a_b + n^a n_b)(Φ_*V)^b=(Φ_*V)^a + n^an_b(Φ_*V)^b[/itex]. So remains to show that the last bit vanishes. The last term vanishes since [itex]a_b[/itex] is normal to [itex](Φ_*V)^b[/itex], so we're done.

Now to generalize for (s, 0) we have:

[tex](⊥(Φ_*T))^{a_1 a_2 ... a_s} = ^{a_1} _{b_1}...⊥^{a_s} _{b_s}(Φ_*T)^{b_1 ... b_s} = (\delta^{a_1}_{b1} + n^{a_1} n_{b_1}) ... (\delta^{a_s}_{b_s} + n^{a_s} n_{b_s})(Φ_*T)^{b_1 ... b_s}[/tex]

My problem is that I'm not quite sure what does it mean to act [itex]n_{b_s} (Φ_*T)^{b_1 ... b_s}[/itex], notion of orthogonality is easily understood for two vectors, but for vector and a tensor I'm not sure. Any ideas much appreciated!
 
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  • #2
Would it help to think of the tensor in terms of (a sum of) tensor products of basis vectors?
 

1. What is the definition of "projecting push forward of a vector"?

"Projecting push forward of a vector" refers to the process of taking a vector and projecting it onto a given space or surface, while also accounting for any changes in the direction or magnitude of the vector.

2. Why is projecting push forward of a vector important?

This process is important in many fields of science, including physics, engineering, and mathematics. It allows for the analysis and understanding of how vectors behave when projected onto different surfaces or spaces, which can have practical applications in real-world situations.

3. How is projecting push forward of a vector calculated?

The calculation for projecting push forward of a vector involves using mathematical formulas and principles such as dot products, cross products, and projections. It can also involve using vector components and unit vectors to determine the final projected vector.

4. What are some examples of applications for projecting push forward of a vector?

One example is in physics, where this process is used to understand the trajectory of objects in motion, such as projectiles or planets. In engineering, it is used to analyze the forces acting on structures or machines. It is also used in mathematics for geometric and algebraic calculations.

5. Are there any limitations to projecting push forward of a vector?

Yes, there are limitations to this process. For example, it assumes that the vector is being projected onto a flat surface or space, and may not accurately represent the behavior of the vector in more complex or curved surfaces. Additionally, it may not account for external forces acting on the vector, such as air resistance or friction.

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