How to Find Eigenstates for Value 0 in Projection on Coherent States Paper?

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SUMMARY

This discussion focuses on finding eigenstates for the value 0 in the context of coherent states as presented in a specific paper. The user references Definition 19, which involves the expression $|z \rangle \langle z| = :\exp-(a-z)^\dagger (a-z):$. The conversation highlights that while finding an eigenvector for the value 1 is straightforward, identifying an eigenstate for the value 0 requires further exploration, particularly starting with the coherent ground state where z = 0.

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  • Understanding of coherent states in quantum mechanics
  • Familiarity with the notation and operations involving creation and annihilation operators
  • Knowledge of eigenvalue problems in quantum systems
  • Basic grasp of exponential operators in quantum mechanics
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  • Research the properties of coherent states and their eigenstates
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  • Investigate the implications of the expression $|z \rangle \langle z| = :\exp-(a-z)^\dagger (a-z):$ in quantum state projections
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Quantum physicists, researchers in quantum mechanics, and students studying coherent states and eigenvalue problems will benefit from this discussion.

Heidi
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Homework Statement
this is about coherent states
Relevant Equations
|z><z| = :exp(a-z)^\dagger (a-z):
i am reading this paper . in the definition 19 we have
|z><z| = :exp(a-z)^\dagger (a-z):
in the extansion the first term is the identity son it is not hart to find an eigenvector for the value 1. it is ok if the vector is annihilated by a. if is the case for the coherent grouns state. how to find an eigenstate for the value 0 ?
 
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It would be simpler to begin with z = 0>
 
I made a typo. The definition is not $ |z><z| = :exp(a-z)^\dagger (a-z): $
it is

$ |z \rangle \langle z| = :exp-(a-z)^\dagger (a-z):$
$
 

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