Proof Check: Geometry AB=EF If A=/B

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SUMMARY

The discussion focuses on proving that if A and B are distinct points on line EF, then the line segment AB is equal to line EF. The proof utilizes the axiom that two distinct points determine a unique line. By establishing that the intersection of the lines defined by points A and B (line X) and line EF (line Y) contains at least two distinct points, it concludes that lines X and Y are identical, thus confirming that AB equals EF.

PREREQUISITES
  • Understanding of basic geometric axioms, specifically the axiom that two points determine a unique line.
  • Familiarity with the concept of line intersection and distinct points in geometry.
  • Knowledge of geometric notation, particularly the representation of points and lines.
  • Basic proof techniques in geometry, including direct proof and logical reasoning.
NEXT STEPS
  • Study the properties of line segments and their relationships in Euclidean geometry.
  • Explore the implications of the axiom that two points determine a unique line in various geometric contexts.
  • Learn about different types of proofs in geometry, including indirect proofs and proof by contradiction.
  • Investigate the concept of line intersections and their significance in geometric proofs.
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Students of geometry, educators teaching geometric principles, and anyone interested in understanding fundamental proof techniques in mathematics.

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Homework Statement



Let A and B be elements of the line EF such that A=/B prove that the line AB=EF

Homework Equations



Axiom that two points determine a unique line and that the intersection of two lines has two distinct points then these lines are the same.

The Attempt at a Solution


[/B]
If A and B are two distinct points they then determine a unique line say X. Let EF=Y then the intersection of X and Y contains at least two distinct points therefore X=Y so AB=EF. Is that sufficient?
 
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Loststudent22 said:

Homework Statement



Let A and B be elements of the line EF such that A=/B prove that the line AB=EF
What do you mean by A=/B?

Are A and B points in the line segment EF?
Loststudent22 said:

Homework Equations



Axiom that two points determine a unique line and that the intersection of two lines has two distinct points then these lines are the same.

The Attempt at a Solution


[/B]
If A and B are two distinct points they then determine a unique line say X. Let EF=Y then the intersection of X and Y contains at least two distinct points therefore X=Y so AB=EF. Is that sufficient?
 

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