Proof: f = g + h, Even & Odd Functions

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Discussion Overview

The discussion revolves around the mathematical proof that a continuous function f defined on the interval (-∞, ∞) can be expressed as the sum of an even function g and an odd function h. Participants explore the properties of even and odd functions and how they relate to the original function f.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant requests assistance in proving that a continuous function f can be decomposed into an even function g and an odd function h.
  • Another participant notes that if f(x) = g(x) + h(x), then f(-x) can be expressed in terms of g and h, prompting further exploration of the properties of these functions.
  • A participant suggests using the properties of even and odd functions to construct g and h from f.
  • There is a calculation presented showing that f(-x) = g(x) - h(x), which leads to a question about whether this is the complete solution.
  • Another participant asks what f(x) + f(-x) equals and seeks clarification on how to explicitly define g(x) and h(x).

Areas of Agreement / Disagreement

The discussion remains unresolved, with participants exploring different aspects of the proof without reaching a consensus on the definitions or final forms of g and h.

Contextual Notes

Participants have not yet established the specific forms of the even and odd functions or the assumptions necessary for the proof, leaving some steps and definitions ambiguous.

javi438
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say function f is continuous on (-[tex]\infty[/tex],[tex]\infty[/tex]). show that f can be written as f = g + h, where g is an even function and h is an odd function.

help pleaseee!
 
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If f(x)=g(x)+h(x) where g is even and h is odd, then what is f(-x)?
 
yeah, use those properties to help you construct your g and h out of f's
 
f(-x) = g(-x) + h(-x)
f(-x) = g(x) - h(x)
= g(x) + (-h(x))

is that it??
 
Ok, then what is f(x)+f(-x)? Then what is g(x), and finally what is h(x)?
 

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