Proof of Chinese Remainder Theory

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SUMMARY

The discussion centers on the Chinese Remainder Theorem (CRT), specifically addressing the proof involving relatively prime integers m and n. The theorem asserts that for any integers s and t, there exists an integer x that satisfies the simultaneous congruences x ≡ s (mod m) and x ≡ t (mod n). The proof utilizes the Euclidean algorithm to express 1 as a linear combination of m and n, leading to the formulation x = (mp)t + (nq)s, which is derived from the coefficients p and q obtained from the algorithm.

PREREQUISITES
  • Understanding of modular arithmetic and congruences
  • Familiarity with the Euclidean algorithm
  • Knowledge of integer linear combinations
  • Basic concepts of number theory
NEXT STEPS
  • Study the proof of the Chinese Remainder Theorem in detail
  • Explore applications of the Chinese Remainder Theorem in cryptography
  • Learn about the Euclidean algorithm and its applications
  • Investigate integer linear combinations and their significance in number theory
USEFUL FOR

Mathematics students, particularly those studying number theory, educators teaching modular arithmetic, and anyone interested in the applications of the Chinese Remainder Theorem in computational mathematics.

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Homework Statement



theorem: Let m and n be relatively prime integers. If s and t are arbitrary integers there exists a solution x in Z to the simultaneous congruences:
x~s (mod m) and x~t (mod n)

Part of proof that confuses me: Since gcd(m,n) = 1, the Euclidean algorithm gives p and q in Z such that 1 = mp + nq. Take x = (mp)t + (nq)s.

How do they get the "Take x = (mp)t + (nq)s" part?

Homework Equations





The Attempt at a Solution

 
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The Chinese remainder theorem says that a solution exists (or, the part you're trying to prove at least). What he's done is told you the form of the solution to the congruences, and will later show that this is always a solution by virtue of its form, thus proving the theorem.
 
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