Proof of determinant properties

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eyehategod
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I need help with proof. Can anyone lead me in the right direction?
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Textbook problem 39: a determinant identity. Left: determinant of a 3x3 matrix with entries a11 to a33, plus a determinant whose first column is b11, b21, b31 and other entries a12 to a33, equals a determinant whose first column is a11+b11, a21+b21, a31+b31 with other entries a12 to a33.
 
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  • Printed textbook exercises 39 and 40 on determinant properties: the determinant of a matrix with first column a11, a21, a31 plus b11, b21, b31 equals the sum of two determinants, with the sum shown in the first column.
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The determinant is a multilinear function of the columns. That means every term in the polynomial expansion of the determinant contains exactly one entry from the first column. How's that for a direction? Think about expanding by minors.
 
A related problem (actually a special case)... concerning cross-products involving vectors A, B, and M.(A x M) + (B x M) = (A+B) x M

Can you do the 2x2 version of your question? The 1x1 is easy.
 
Dick said:
The determinant is a multilinear function of the columns. That means every term in the polynomial expansion of the determinant contains exactly one entry from the first column. How's that for a direction? Think about expanding by minors.

eyehategod said:
Im still lost. I am not understanding.
Do you know how to "expand by minors"? If so find the determinant on the right by expanding along the first column.
 
Look up 'expansion by minors'. You can turn the first 3x3 determinant into a sum of three 2x2 determinants a_11*A_11-a_21*A_21+a_31*A_31, where A_ij is a 2x2 determinant that doesn't include any elements of the first column. The second one is b_11*A_11-b_21*A_21+b_31*A_31. The important thing is that the A determinants are the same.