MHB Proof of Infinitely Many Units of Z[sqrt n] for Eacn Non-Square Natural Number

AI Thread Summary
The discussion focuses on proving that the ring of integers extended by the square root of any non-square natural number, denoted as Z[√n], contains infinitely many units. Participants suggest applying Dirichlet's Unit Theorem as a primary method for this proof. Additionally, a diophantine approach involving the equation x² - ny² = ±1 is mentioned, which relates to Pell's equation and can yield infinite solutions. The conversation emphasizes the importance of understanding these mathematical concepts to tackle the exercise effectively. The thread highlights the interconnectedness of number theory and diophantine equations in proving the existence of infinitely many units.
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In John Stillwell's book: Elements of Number Theory, Exercise 6.1.3 reads as follows:

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Show that $$\mathbb{Z} [ \sqrt{n}$$ has infinitely many units for any non-square natural number n

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Can someone please help me get started on this exercise?

Peter
 
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Peter said:
In John Stillwell's book: Elements of Number Theory, Exercise 6.1.3 reads as follows:

-------------------------------------------------------------------------------------------------

Show that $$\mathbb{Z} [ \sqrt{n}$$ has infinitely many units for any non-square natural number n

-------------------------------------------------------------------------------------------------

Can someone please help me get started on this exercise?

Peter

Hint: Apply Dirchlet's unit theorem to $\Bbb Z[\sqrt{n}]$.
 
Euge said:
Hint: Apply Dirchlet's unit theorem to $\Bbb Z[\sqrt{n}]$.

Another relatively diophantine approach would be to look at $x^2 - ny^2 = \pm 1$. Appropriate diophantine approximations on $\sqrt{n}$ can produce at least one solution to $x^2 - ny^2 = 1$, thus producing infinitely many of them by fundamental results on Pell equation.
 
Euge said:
Hint: Apply Dirchlet's unit theorem to $\Bbb Z[\sqrt{n}]$.
Thanks Euge ...

Will have to read up on Dirichlet's Unit Theorem ...

Peter

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mathbalarka said:
Another relatively diophantine approach would be to look at $x^2 - ny^2 = \pm 1$. Appropriate diophantine approximations on $\sqrt{n}$ can produce at least one solution to $x^2 - ny^2 = 1$, thus producing infinitely many of them by fundamental results on Pell equation.

Thanks Mathbalarka ...

Will have to read up on The Pell equation to be able to follow your advice ...

Peter
 
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