MHB Proof of Inner Product in E with Orthonormal Sequence (n=positive integer)

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In the discussion about proving the inner product in an inner product space E with an orthonormal sequence (e_n), participants focus on the expression Re(<x,(<x,e_1>+...<x,e_k>)e_n>). The main point of contention is the presence of the variable k on the left side of the equation, which some believe should not be there. The correct formulation suggested is that the inner product should equal the sum of the squares of the magnitudes of the inner products with the orthonormal basis vectors. Clarification on how to compute the real part of the inner product is also sought, indicating some confusion about the notation and the proof's structure. The discussion highlights the need for precision in mathematical expressions and the importance of consistent notation.
Poirot1
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let E be an inner product space and (e_n) an orthonormal sequence in E. For x in E and any positive integer n, prove that

Re(<x,(<x,e_1>+...<x,e_k>)e_n>)= |<x,e_1>|^2+...+|<x,e_n>|^2

I got <x,(<x,e_1>+...<x,e_k>)e_n>= <<x,e_1>e_1,x>+...<<x,e_n>e_n,x>

but haven't a clue how to find the real part of this. Sorry for the ugly subscript notation.
 
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Re: inner product proof

Poirot said:
let E be an inner product space and (e_n) an orthonormal sequence in E. For x in E and any positive integer n, prove that

Re(<x,(<x,e_1>+...<x,e_k>)e_n>)= |<x,e_1>|^2+...+|<x,e_n>|^2

I got <x,(<x,e_1>+...<x,e_k>)e_n>= <<x,e_1>e_1,x>+...<<x,e_n>e_n,x>

but haven't a clue how to find the real part of this. Sorry for the ugly subscript notation.
This looks wrong to me. Why is there a $k$ on the left side but not on the right? I think that the result should be $$\bigl\langle x,\langle x,x_1\rangle e_1 + \ldots + \langle x,x_n\rangle e_n\bigr\rangle = |\langle x,e_1\rangle|^2 + \ldots + |\langle x,e_n\rangle|^2.$$
 

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