How to Prove the Limit as n Goes to Infinity of a^(1/n) = 1

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SUMMARY

The limit as n approaches infinity of a^(1/n) equals 1 for any constant a greater than 1. The proof involves demonstrating that for any ε > 0, there exists an N such that for all n > N, the inequality |a^(1/n) - 1| < ε holds true. The value of N can be determined as N = (a - 1)/ε, which establishes the necessary condition for the limit. This proof utilizes the properties of exponential functions and the definition of limits in calculus.

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Homework Statement


Let a>1. Prove the limit as n goes to \infty of a1/n = 1.

The Attempt at a Solution


Given \epsilon > 0, \foralln>N, |a1/n-L|<\epsilon and N=(a-1)/\epsilon.
|a1/n-L| = a1/n-1


...and that's where I get confused. I know that I have to multiply (a1/n-1) by something but I'm not sure what exactly (a hint my professor gave).
 
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Here's a hint that may or may not help. You want |a^(1/n) - 1| < e. So for example, perhaps you want |a^(1/n) - 1| = e/2.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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