Proof that gravity equals 9.8 metres per second?

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SUMMARY

The discussion confirms that gravity approximates 9.8 meters per second squared under ideal conditions, specifically in a vacuum where air resistance is eliminated. Participants emphasize the necessity of controlling for variables such as air friction and latitude variations to achieve accurate measurements. Traditional methods, including the use of ticker tape and pendulum experiments, are recommended for approximating gravitational acceleration. The consensus is that while the proposed methods yield first-order approximations, measurement errors may overshadow the effects of air resistance unless advanced equipment is utilized.

PREREQUISITES
  • Understanding of gravitational acceleration and its measurement
  • Familiarity with experimental physics concepts, particularly in vacuum conditions
  • Knowledge of traditional measurement techniques, such as ticker tape timing
  • Basic principles of pendulum motion and its relation to gravity
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  • Research the effects of air resistance on falling objects in various environments
  • Learn about vacuum chamber experiments for precise measurement of gravitational acceleration
  • Explore the mathematical derivation of gravitational acceleration using pendulum time periods
  • Investigate historical experiments conducted by Galileo and their relevance to modern physics
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Students of physics, educators conducting experiments on gravity, and anyone interested in the practical applications of gravitational measurement techniques.

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If you had to confirm that gravity equals approximately 9.8 metres per second would you take an object and drop it from different heights. Would you then take the time and displacement and work out velocity and then use that to work out acceleration??

EDIT: In this example there is no air resistance
 
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the experiment won't give exactly 9.8 , since air friction is also there .
You need vacuum or vacuum like condition for 9.8 .
And g also varies with latitudes .
 
kushan said:
the experiment won't give exactly 9.8 , since air friction is also there .
You need vacuum or vacuum like condition for 9.8 .
And g also varies with latitudes .

That's why I said approximately 9.8.
Is my method correct?
 
, you need to eliminate air resistance
 
kushan said:
, you need to eliminate air resistance

Thank you
 
You're method is good enough for a first order approximation.
 
Your measurement errors will be greater then the effects of air resistance unless you have some pretty exotic equipment.

The traditional method for doing this was to fasten a strip of waxed paper tape to your weight and feed it through a sparker with a know rate. The distance between the dots give you the displacement in fixed time intervals.
 
Integral said:
Your measurement errors will be greater then the effects of air resistance unless you have some pretty exotic equipment.

The traditional method for doing this was to fasten a strip of waxed paper tape to your weight and feed it through a sparker with a know rate. The distance between the dots give you the displacement in fixed time intervals.

I understand. Like the "ticker tape"?
 
And you can also make a pendulum of a heavy mass , light spring .
Calculate its time period ( keep the amplitude small ) , and plug it in the equation of of time period , you can find g , pretty close enough .
 
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Galileo used the inclined plane.
 

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