Propelling force due to an orifice

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SUMMARY

The discussion focuses on calculating the propelling force on a trolley due to water flowing from an orifice in a tank. The tank is 1.5m high with a 0.1m diameter orifice located 0.3m from the bottom. The coefficient of discharge is 0.60, leading to a calculated propelling force of 67.39N. The correct approach involves using the formula F = c * ρ * A * v², where the velocity of flow through the orifice is determined to be 4.84 m/s using the equation √(2gh).

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  • Familiarity with Newton's third law of motion.
  • Knowledge of the coefficient of discharge and its application.
  • Ability to perform calculations involving velocity and force.
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  • Explore the relationship between flow velocity and pressure in fluid systems.
  • Investigate the impact of orifice diameter on flow rate and force calculations.
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Homework Statement


A tank 1.5m high stands on a trolley and is full of water .it has an orifice of diameter 0.1m at 0.3m from the bottom of the tank.if the orifice is suddenly opened coefficient of discharge of the orifice is 0.60, then find propelling force on the trolley.
Ans: 67.39N

Homework Equations


F=c⋅ρ⋅A⋅v^2

The Attempt at a Solution


It looks like a simple problem based on Newton's third law of motion where the propelling force on the trolley must be equal to the change in momentum of the liquid jet coming out of the orfice.

thus F= 0.6X10^3X (Π/4)0.1^2X2X9.8X1.2
=110.35
which is not correct.

I am not getting what's wrong with my approach.
 
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What is the velocity of the flow through the orifice ?
 
Nidum said:
What is the velocity of the flow through the orifice ? Why is this relevant ?
velocity of the flow will be: √(2gh)=√(2X9.8X1.2) =4.84
didn't understand next part
 

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