MHB Property of Matrix Multiplication

[Yankel]

Hello, I wanted to ask if this is a correct move, A and B are matrices, a is a scalar, thank you !

A^{2}\cdot B^{t}-aA=A(A\cdot B^{t}-aI)

 

[caffeinemachine]

Hello, I wanted to ask if this is a correct move, A and B are matrices, a is a scalar, thank you !

A^{2}\cdot B^{t}-aA=A(A\cdot B^{t}-aI)

Seems correct to me.

 

[Sudharaka]

Hello, I wanted to ask if this is a correct move, A and B are matrices, a is a scalar, thank you !

A^{2}\cdot B^{t}-aA=A(A\cdot B^{t}-aI)

Hi Yankel, :)

Yes, its correct because matrix multiplication is distributive over matrix addition.

Kind Regards,
Sudharaka.

 

[Yankel]

Thank you !