Property of the adjoint operator

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Discussion Overview

The discussion revolves around the properties of the adjoint operator in the context of inner product spaces, specifically focusing on the adjoint of a scalar multiplied operator and the adjoint of the product of two operators. Participants explore how to demonstrate these properties using the definitions and characteristics of inner products.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant defines the adjoint of an operator A and poses a question about using inner product properties to show that (cA)* = c*P*.
  • Another participant questions the notation used and seeks clarification on what \dag does, suggesting that A and P might be the same operator.
  • A participant acknowledges the notation confusion and proposes using the skew-symmetry property of inner products to relate <\phi|cA\psi> and , but expresses uncertainty about its utility.
  • Another participant suggests that the definition of scalar multiplication with operators and properties of the inner product can be used to derive (cA)* in a few steps.
  • A different participant provides a step in the reasoning, showing how <(cA)x|y> can be expressed in terms of and , leading towards a conclusion about (cA)*.
  • One participant raises the property of the adjoint of a product of operators, (PQ)^{\dag} = Q^{\dag}P^{\dag}, and expresses that this property appears more challenging to demonstrate.
  • Another participant counters that they do not find the property difficult and suggests starting with the definition of the inner product.

Areas of Agreement / Disagreement

Participants express various viewpoints on the properties of adjoint operators, with some agreeing on the approach to demonstrate (cA)* while others find the property of the adjoint of a product more complex. No consensus is reached on the difficulty of the latter property.

Contextual Notes

Participants rely on specific properties of inner products, such as skew-symmetry and linearity, but the discussion does not fully resolve the implications of these properties or the definitions involved.

ehrenfest
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The adjoint of an operator A is defined as an operator A* s.t.

[tex]<\phi|A\psi> = <A^{*}\phi|\psi>[/tex].

How would you use the properties of inner products (skew-symmetry, positive semi-definiteness, and linearity in ket) to show that (cA)* = c*P*


Note that I am using the conjugate and the adjoint symbol interchangeably. If anyone knows how to get a real adjoint symbol in LaTeX let me know.
 
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what does \dag do? I assume that A and P are supposed to be the same letter... and then it is trivial. What have you attempted?
 
Yes sorry. A and P are supposed to be the same letter.

You could use the skew-symmetry property to show that:

[tex]<\phi|cA\psi> = <cA\psi|\phi>^{*}[/tex]

and that

[tex]<cA^{\dag}\phi|\psi> = <\psi|cA^{\dag}\phi>^{*}[/tex]

but I do not see how that helps.
 
((cA)x | y) = ...

Unless I'm mistaken, you have to use the definition of scalar multiplication with operators, and two peoperties of the inner product. In three (four) steps, you can show what (cA)* equals.
 
I see. So, [tex]<(cA)x|y> = c*<Ax|y> = c*<x|A^{\dag}y> = < x|c*A^{\dag}y>[/tex].
 
What about the property [tex](PQ)^{\dag} = Q^{\dag}P^{\dag}[/tex]? This one seems a bit more difficult.
 
ehrenfest said:
What about the property [tex](PQ)^{\dag} = Q^{\dag}P^{\dag}[/tex]? This one seems a bit more difficult.

I wouldn't really call it difficult. Again, ( (PQ)x | y ) = ...
 

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